借小丑牌的赌注档:同一道题加一条限制(「整首歌只用 1 次 print」)再做一遍, 给课上做得快的学生找事做(做完一节课的题,中位要空等 13 分钟)。 判定沿用 AST 规则,挑战配在 problem.challenges,做到的记在 challenge_success; 做对的提交顺手判一遍,挑战没做到也照样算做对。没过的规则带上是第几行。 0039 灌进第一批 56 道常用题的 73 条挑战,api 起来后拿历史上做对的代码补一遍谁已经做到了。 出题页能配挑战、从做对的代码里找候选;课堂看板的格子带上挑战状态。 Co-Authored-By: Claude Opus 5.5 <noreply@anthropic.com>
15 lines
1.3 KiB
SQL
15 lines
1.3 KiB
SQL
CREATE TABLE "challenge_success" (
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"id" integer PRIMARY KEY GENERATED BY DEFAULT AS IDENTITY (sequence name "challenge_success_id_seq" INCREMENT BY 1 MINVALUE 1 MAXVALUE 2147483647 START WITH 1 CACHE 1),
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"user_id" integer NOT NULL,
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"problem_id" integer NOT NULL,
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"challenge_id" text NOT NULL,
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"submission_id" text NOT NULL,
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"created_at" timestamp with time zone NOT NULL,
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CONSTRAINT "challenge_success_user_challenge_unique" UNIQUE("user_id","problem_id","challenge_id")
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);
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--> statement-breakpoint
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ALTER TABLE "problem" ADD COLUMN "challenges" jsonb;--> statement-breakpoint
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ALTER TABLE "challenge_success" ADD CONSTRAINT "challenge_success_user_id_fk_user_id" FOREIGN KEY ("user_id") REFERENCES "public"."user"("id") ON DELETE no action ON UPDATE no action;--> statement-breakpoint
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ALTER TABLE "challenge_success" ADD CONSTRAINT "challenge_success_problem_id_fk_problem_id" FOREIGN KEY ("problem_id") REFERENCES "public"."problem"("id") ON DELETE cascade ON UPDATE no action;--> statement-breakpoint
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ALTER TABLE "challenge_success" ADD CONSTRAINT "challenge_success_submission_id_fk_submission_id" FOREIGN KEY ("submission_id") REFERENCES "public"."submission"("id") ON DELETE cascade ON UPDATE no action;--> statement-breakpoint
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CREATE INDEX "challenge_success_problem_idx" ON "challenge_success" USING btree ("problem_id","challenge_id","created_at"); |