新增 mid_ac_count / hard_ac_count,去重统计中等和困难难度的 AC 题数。 在此之前所有成就对水题和难题一视同仁,这是最缺的一个维度。 增量走 build_ctx 新增的 problem_difficulty,它只在首次 AC 时才查库—— 绝大多数提交都不是首次 AC,无条件预查等于给每次判题白加一条 SQL。 删除 min_ac_code_chars:线上实测 1314 个用户的分布,最小值 8、p5=10, 有道题 8 个字符就能通过,这个指标测的是"谁做过那道水题"而不是 "谁写得简洁",配不出有意义的成就。 自检里写死 min_ac_code_chars 的两处改成按 lte 成就自动发现: _check_registry 不再要求某个具体指标存在,_check_min_metric_absent 改为遍历所有上架的 lte 成就检查其指标。没有 lte 成就时 SKIP, 将来配了自动开始检查。 Co-Authored-By: Claude Opus 5 <noreply@anthropic.com>
404 lines
16 KiB
Python
404 lines
16 KiB
Python
"""成就指标注册表。
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这里定义"能测量什么",后台定义"多少算达成"。管理员在后台看到的指标下拉框
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就是 METRIC_REGISTRY 的 key 列表。加一个新维度必须改本文件并部署,
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之后在该维度上加任意多条成就都是纯配置。
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约定:指标从未产生过有效值时,recompute 返回 None,调用方删除该 key。
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metrics 字典里 key 不存在 == 未达标,判定时直接跳过。
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"""
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import logging
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from django.db.models import Count, Q
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from django.utils import timezone
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from submission.models import JudgeStatus, Submission, is_accepted
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from utils.constants import Difficulty
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logger = logging.getLogger(__name__)
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METRIC_REGISTRY = {}
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META_METRICS = set()
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# AC 口径与全项目一致:AST_CHECK_FAILED(代码结构检查未通过但测试点全过)也算通过。
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# 见 submission/models.py 的 is_accepted()。ORM 过滤用这个常量,标量比较用 is_accepted()。
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ACCEPTED_RESULTS = (JudgeStatus.ACCEPTED, JudgeStatus.AST_CHECK_FAILED)
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class BaseMetric:
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key = ""
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name = ""
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help_text = ""
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def on_submission(self, metrics, sub, ctx):
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"""判题完成后增量更新 metrics(原地修改)。"""
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raise NotImplementedError
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def recompute(self, user):
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"""全量重算。返回 None 表示该用户此指标无有效值。"""
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raise NotImplementedError
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def recompute_state(self, user):
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"""重算时一并重建增量所需的辅助键,返回 {key: value}。
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默认无辅助状态。凡是 on_submission 依赖 `_` 前缀辅助键的指标都必须重写
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本方法:否则全量重算把辅助键丢掉后,下一次判题会从零重新累积,指标当场
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回退(active_days 从 45 掉回 1),且要等到下一次重算才恢复。
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"""
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return {}
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def metric(key, name, help_text="", meta=False):
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def deco(cls):
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cls.key = key
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cls.name = name
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cls.help_text = help_text
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METRIC_REGISTRY[key] = cls()
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if meta:
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META_METRICS.add(key)
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return cls
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return deco
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def _practice_submissions(user_id):
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"""成就只统计平时练习的提交,比赛提交不计入。"""
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return Submission.objects.filter(user_id=user_id, contest_id__isnull=True)
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def build_ctx(user_id, sub):
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"""判题后预查一次,所有指标复用,避免每个指标各自查库。
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比赛提交不参与成就统计,此时返回 skip=True,调用方直接跳过整轮判定。
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"""
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if sub.contest_id is not None:
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return {"skip": True}
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prior = _practice_submissions(user_id).filter(problem_id=sub.problem_id).exclude(id=sub.id)
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prior_stats = prior.aggregate(
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total=Count("id"),
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accepted=Count("id", filter=Q(result__in=ACCEPTED_RESULTS)),
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)
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local_now = timezone.localtime(sub.create_time)
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sub_is_accepted = is_accepted(sub.result)
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is_first_ac_of_problem = sub_is_accepted and prior_stats["accepted"] == 0
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# 难度只有首次 AC 时才用得上,其余情况不查这一次库——
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# 绝大多数提交都不是首次 AC,放在外面等于给每次判题白加一条 SQL
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difficulty = None
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if is_first_ac_of_problem:
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from problem.models import Problem
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difficulty = Problem.objects.filter(id=sub.problem_id).values_list("difficulty", flat=True).first()
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return {
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"skip": False,
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"is_accepted": sub_is_accepted,
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# 该题此前的提交次数与 AC 次数
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"prior_count": prior_stats["total"],
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"prior_accepted": prior_stats["accepted"],
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# 首次 AC 这道题(此前从未 AC 过)
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"is_first_ac_of_problem": is_first_ac_of_problem,
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# 一发入魂:此前无任何提交且本次 AC
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"is_first_try_ac": sub_is_accepted and prior_stats["total"] == 0,
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# 本题难度,仅首次 AC 时有值
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"problem_difficulty": difficulty,
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"local_date": local_now.date().isoformat(),
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"local_hour": local_now.hour,
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}
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@metric("accepted_count", "AC 题目数", "去重后通过的题目数量(不含比赛)")
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class AcceptedCount(BaseMetric):
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def on_submission(self, metrics, sub, ctx):
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if ctx["is_first_ac_of_problem"]:
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metrics["accepted_count"] = metrics.get("accepted_count", 0) + 1
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def recompute(self, user):
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return _practice_submissions(user.id).filter(result__in=ACCEPTED_RESULTS).order_by().values("problem_id").distinct().count()
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class _DifficultyAcCount(BaseMetric):
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"""按难度去重统计 AC 题数。子类只需指定 difficulty。
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增量靠 ctx["problem_difficulty"],它只在首次 AC 时才有值——与
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is_first_ac_of_problem 是同一个条件,所以两者一起判即可。
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"""
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difficulty = ""
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def on_submission(self, metrics, sub, ctx):
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if ctx["is_first_ac_of_problem"] and ctx["problem_difficulty"] == self.difficulty:
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metrics[self.key] = metrics.get(self.key, 0) + 1
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def recompute(self, user):
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return _practice_submissions(user.id).filter(result__in=ACCEPTED_RESULTS, problem__difficulty=self.difficulty).order_by().values("problem_id").distinct().count()
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@metric("mid_ac_count", "中等题 AC 数", "去重后通过的中等难度题目数(不含比赛)")
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class MidAcCount(_DifficultyAcCount):
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difficulty = Difficulty.MID
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@metric("hard_ac_count", "困难题 AC 数", "去重后通过的困难题目数(不含比赛)")
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class HardAcCount(_DifficultyAcCount):
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difficulty = Difficulty.HIGH
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@metric("submission_count", "提交总数", "提交次数(不含比赛)")
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class SubmissionCount(BaseMetric):
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def on_submission(self, metrics, sub, ctx):
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metrics["submission_count"] = metrics.get("submission_count", 0) + 1
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def recompute(self, user):
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return _practice_submissions(user.id).count()
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@metric("active_days", "活跃天数", "有过提交的累计天数")
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class ActiveDays(BaseMetric):
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def on_submission(self, metrics, sub, ctx):
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seen = metrics.get("_active_dates", [])
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if ctx["local_date"] not in seen:
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seen.append(ctx["local_date"])
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metrics["_active_dates"] = seen
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metrics["active_days"] = len(seen)
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def recompute(self, user):
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dates = {timezone.localtime(t).date().isoformat() for t in _practice_submissions(user.id).values_list("create_time", flat=True)}
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return len(dates)
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def recompute_state(self, user):
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dates = sorted({timezone.localtime(t).date().isoformat() for t in _practice_submissions(user.id).values_list("create_time", flat=True)})
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return {"_active_dates": dates}
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@metric("max_ac_streak_days", "最长连续 AC 天数", "连续每天至少 AC 一题的最长天数")
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class MaxAcStreakDays(BaseMetric):
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def on_submission(self, metrics, sub, ctx):
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if not ctx["is_accepted"]:
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return
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today = ctx["local_date"]
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last = metrics.get("_last_ac_date")
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if last == today:
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return
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current = metrics.get("_current_ac_streak", 0)
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if last and (timezone.datetime.fromisoformat(today) - timezone.datetime.fromisoformat(last)).days == 1:
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current += 1
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else:
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current = 1
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metrics["_last_ac_date"] = today
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metrics["_current_ac_streak"] = current
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metrics["max_ac_streak_days"] = max(metrics.get("max_ac_streak_days", 0), current)
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def recompute(self, user):
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dates = sorted({timezone.localtime(t).date() for t in _practice_submissions(user.id).filter(result__in=ACCEPTED_RESULTS).values_list("create_time", flat=True)})
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if not dates:
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return None
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best = current = 1
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for prev, cur in zip(dates, dates[1:]):
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current = current + 1 if (cur - prev).days == 1 else 1
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best = max(best, current)
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return best
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def recompute_state(self, user):
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dates = sorted({timezone.localtime(t).date() for t in _practice_submissions(user.id).filter(result__in=ACCEPTED_RESULTS).values_list("create_time", flat=True)})
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if not dates:
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return {}
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current = 1
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for prev, cur in zip(dates, dates[1:]):
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current = current + 1 if (cur - prev).days == 1 else 1
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return {"_last_ac_date": dates[-1].isoformat(), "_current_ac_streak": current}
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@metric("languages_used", "使用语言数", "用过多少种编程语言")
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class LanguagesUsed(BaseMetric):
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def on_submission(self, metrics, sub, ctx):
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seen = metrics.get("_languages", [])
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if sub.language not in seen:
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seen.append(sub.language)
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metrics["_languages"] = seen
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metrics["languages_used"] = len(seen)
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def recompute(self, user):
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return _practice_submissions(user.id).order_by().values("language").distinct().count()
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def recompute_state(self, user):
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# order_by() 不能省:Submission.Meta 有默认排序 ("-create_time",),
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# Django 会把排序字段并入 DISTINCT,于是每条提交各成一行——
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# 实测某用户返回 659 条而不是 5 种语言。
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# recompute 侥幸正确只是因为 .count() 会清掉排序,不能依赖这一点。
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return {"_languages": list(_practice_submissions(user.id).order_by().values_list("language", flat=True).distinct())}
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@metric("contest_joined", "参赛场次", "参加过的比赛数量(本指标是比赛维度,不受比赛提交不计入的限制)")
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class ContestJoined(BaseMetric):
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def on_submission(self, metrics, sub, ctx):
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# 比赛提交在 build_ctx 就被跳过,本指标只走 recompute
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return
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def recompute(self, user):
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return Submission.objects.filter(user_id=user.id, contest_id__isnull=False).order_by().values("contest_id").distinct().count()
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@metric("badge_count", "题单奖章数", "获得的题单奖章数量")
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class BadgeCount(BaseMetric):
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def on_submission(self, metrics, sub, ctx):
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# 奖章由题单流程颁发,本指标只走 recompute,见 Task 7
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return
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def recompute(self, user):
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from problemset.models import UserBadge
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return UserBadge.objects.filter(user=user).count()
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@metric("problemset_completed", "完成题单数", "完成的题单数量")
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class ProblemSetCompleted(BaseMetric):
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def on_submission(self, metrics, sub, ctx):
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return
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def recompute(self, user):
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from problemset.models import ProblemSetProgress
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return ProblemSetProgress.objects.filter(user=user, complete_time__isnull=False).count()
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@metric("first_try_ac_count", "一发入魂次数", "首次提交即通过的次数")
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class FirstTryAcCount(BaseMetric):
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def on_submission(self, metrics, sub, ctx):
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if ctx["is_first_try_ac"]:
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metrics["first_try_ac_count"] = metrics.get("first_try_ac_count", 0) + 1
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def recompute(self, user):
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count = 0
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seen = set()
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for s in _practice_submissions(user.id).order_by("create_time").values("problem_id", "result"):
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if s["problem_id"] in seen:
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continue
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seen.add(s["problem_id"])
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if is_accepted(s["result"]):
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count += 1
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return count
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@metric("midnight_submissions", "凌晨提交次数", "0:00–5:00 之间的提交次数")
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class MidnightSubmissions(BaseMetric):
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def on_submission(self, metrics, sub, ctx):
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if 0 <= ctx["local_hour"] < 5:
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metrics["midnight_submissions"] = metrics.get("midnight_submissions", 0) + 1
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def recompute(self, user):
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return sum(1 for t in _practice_submissions(user.id).values_list("create_time", flat=True) if 0 <= timezone.localtime(t).hour < 5)
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@metric("early_bird_submissions", "早起提交次数", "5:00–7:00 之间的提交次数")
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class EarlyBirdSubmissions(BaseMetric):
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"""与 midnight_submissions 对称的作息维度。5 点是两者的分界,不重叠。"""
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def on_submission(self, metrics, sub, ctx):
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if 5 <= ctx["local_hour"] < 7:
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metrics["early_bird_submissions"] = metrics.get("early_bird_submissions", 0) + 1
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def recompute(self, user):
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return sum(1 for t in _practice_submissions(user.id).values_list("create_time", flat=True) if 5 <= timezone.localtime(t).hour < 7)
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@metric("compile_error_count", "编译错误次数", "累计编译错误的次数")
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class CompileErrorCount(BaseMetric):
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def on_submission(self, metrics, sub, ctx):
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if sub.result == JudgeStatus.COMPILE_ERROR:
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metrics["compile_error_count"] = metrics.get("compile_error_count", 0) + 1
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def recompute(self, user):
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return _practice_submissions(user.id).filter(result=JudgeStatus.COMPILE_ERROR).count()
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@metric("max_wa_before_ac", "屡败屡战", "单题失败最多多少次后终于通过")
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class MaxWaBeforeAc(BaseMetric):
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def on_submission(self, metrics, sub, ctx):
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if ctx["is_first_ac_of_problem"]:
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metrics["max_wa_before_ac"] = max(metrics.get("max_wa_before_ac", 0), ctx["prior_count"])
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def recompute(self, user):
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best = None
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attempts = {}
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for s in _practice_submissions(user.id).order_by("create_time").values("problem_id", "result"):
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pid = s["problem_id"]
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if pid in attempts and attempts[pid] is None:
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continue
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if is_accepted(s["result"]):
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best = max(best or 0, attempts.get(pid, 0))
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attempts[pid] = None
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else:
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attempts[pid] = attempts.get(pid, 0) + 1
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return best
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@metric("max_ac_in_one_day", "单日最多 AC", "一天之内最多通过多少题")
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class MaxAcInOneDay(BaseMetric):
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def on_submission(self, metrics, sub, ctx):
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if not ctx["is_first_ac_of_problem"]:
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return
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counts = metrics.get("_ac_per_day", {})
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counts[ctx["local_date"]] = counts.get(ctx["local_date"], 0) + 1
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metrics["_ac_per_day"] = counts
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metrics["max_ac_in_one_day"] = max(counts.values())
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def recompute(self, user):
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counts = {}
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seen = set()
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for s in _practice_submissions(user.id).filter(result__in=ACCEPTED_RESULTS).order_by("create_time").values("problem_id", "create_time"):
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if s["problem_id"] in seen:
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continue
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seen.add(s["problem_id"])
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day = timezone.localtime(s["create_time"]).date().isoformat()
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counts[day] = counts.get(day, 0) + 1
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return max(counts.values()) if counts else None
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def recompute_state(self, user):
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counts = {}
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seen = set()
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for s in _practice_submissions(user.id).filter(result__in=ACCEPTED_RESULTS).order_by("create_time").values("problem_id", "create_time"):
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if s["problem_id"] in seen:
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continue
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seen.add(s["problem_id"])
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day = timezone.localtime(s["create_time"]).date().isoformat()
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counts[day] = counts.get(day, 0) + 1
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return {"_ac_per_day": counts}
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# 曾经这里有 min_ac_code_chars(最短 AC 代码)。线上实测 1314 个用户的分布,
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# 最小值 8、p5=10:有道题 8 个字符就能通过,于是它测的是"谁做过那道水题"
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# 而不是"谁写得简洁",配不出有意义的成就,2026-08-05 删除。
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# 要重新引入,得先按题目难度加权,或排除掉那类水题。
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@metric("max_code_lines", "最长代码行数", "提交过的最长代码有多少行")
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class MaxCodeLines(BaseMetric):
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def on_submission(self, metrics, sub, ctx):
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lines = len(sub.code.splitlines())
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metrics["max_code_lines"] = max(metrics.get("max_code_lines", 0), lines)
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def recompute(self, user):
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counts = [len(c.splitlines()) for c in _practice_submissions(user.id).values_list("code", flat=True)]
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return max(counts) if counts else None
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@metric("achievement_unlocked_count", "已解锁成就数", "已解锁的成就数量(不含白金档)", meta=True)
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class AchievementUnlockedCount(BaseMetric):
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"""自引用指标:解锁成就会改变它。
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因此判定流程限定为最多两轮(见 checker.py),且口径排除白金档自身,
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避免「集齐 N 个成就」这类白金奖杯把自己算进分子。
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"""
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def on_submission(self, metrics, sub, ctx):
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# 由 checker 在第一轮解锁后显式重算,不参与增量更新
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return
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def recompute(self, user):
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from achievement.models import Rarity, UserAchievement
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return UserAchievement.objects.filter(user=user).exclude(achievement__rarity=Rarity.PLATINUM).count()
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