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OJ2/apps/api/src/services/learning-stats.ts
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/**
* 学情统计:AI 学情分析页(/ai/detail、/ai/duration、/ai/solved)和喂给模型的
* 数据都从这里算。原来整段放在 routes/ai.ts 里,占了那个文件六成;它们只是查询,
* 不碰 Context,挪出来 route 文件只剩「鉴权 → 取参 → 调这里 → 回包」。
*/
import {
type AiDetail,
type DurationData,
type Grade,
type SolvedList,
type SolvedProblem,
} from "@oj2/contract"
import { and, asc, count, countDistinct, eq, gte, inArray, lte, min, sql } from "drizzle-orm"
import type { AuthUser } from "../auth/session"
import { db, schema } from "../db"
import { JudgeStatus, type JudgeStatusValue } from "../judge/status"
import { rounded } from "../routes/helpers"
import { localTime, shiftMonthsByCalendar } from "../time"
export const accepted: JudgeStatusValue[] = [JudgeStatus.ACCEPTED, JudgeStatus.AST_CHECK_FAILED]
const difficultyNames: Record<string, string> = {
Low: "简单",
Mid: "中等",
High: "困难",
}
function grade(rank: number | null, count: number, reference = count): Grade {
if (!rank || count <= 0) return "C"
const percentile = ((rank - 1) / count) * 100
let value: Grade = percentile < 10 ? "S" : percentile < 35 ? "A" : percentile < 75 ? "B" : "C"
if (reference < 10) value = value === "S" ? "A" : value === "A" ? "B" : value
return value
}
function averageGrade(grades: Grade[]): Grade {
const weights: Record<string, number> = { S: 4, A: 3, B: 2, C: 1 }
const values = grades.flatMap((item) => weights[item] ?? [])
if (!values.length) return ""
const average = values.reduce((sum, value) => sum + value, 0) / values.length
return average >= 3.5 ? "S" : average >= 2.5 ? "A" : average >= 1.5 ? "B" : "C"
}
type FirstAcRow = { problemId: number; first: string | null }
/** 区间内首次 AC 的题,按通过时间升序。limit/offset 给分页用,不传就是全部 */
function firstAcQuery(user: AuthUser, start: string, end: string, limit?: number, offset?: number) {
const first = min(schema.submission.createTime)
const query = db
.select({ problemId: schema.submission.problemId, first })
.from(schema.submission)
.where(
and(
eq(schema.submission.userId, user.id),
inArray(schema.submission.result, accepted),
gte(schema.submission.createTime, start),
lte(schema.submission.createTime, end),
),
)
.groupBy(schema.submission.problemId)
.orderBy(asc(first))
return limit === undefined ? query : query.limit(limit).offset(offset ?? 0)
}
/**
* 把一批「首次 AC」的题算成逐题明细(排名、等级、尝试次数)。
* 排名只跟这批题有关,所以分页那支只需要给一页的 problemIds,不必把整年算一遍。
*/
export async function buildSolved(
user: AuthUser,
start: string,
end: string,
firstAc: FirstAcRow[],
) {
const problemIds = firstAc.map((item) => item.problemId)
if (!problemIds.length)
return {
solved: [],
problems: [] as {
problem: typeof schema.problem.$inferSelect
contestTitle: string | null
}[],
scopeIds: null as number[] | null,
}
const classUsers = user.className
? await db
.select({ id: schema.user.id })
.from(schema.user)
.where(eq(schema.user.className, user.className))
: []
const scopeIds = classUsers.length > 1 ? classUsers.map((item) => item.id) : null
const [problems, rankRows, periodRows, attemptRows] = await Promise.all([
db
.select({ problem: schema.problem, contestTitle: schema.contest.title })
.from(schema.problem)
.leftJoin(schema.contest, eq(schema.problem.contestId, schema.contest.id))
.where(inArray(schema.problem.id, problemIds)),
db
.select({
userId: schema.submission.userId,
problemId: schema.submission.problemId,
first: min(schema.submission.createTime),
})
.from(schema.submission)
.where(
and(
inArray(schema.submission.result, accepted),
inArray(schema.submission.problemId, problemIds),
scopeIds ? inArray(schema.submission.userId, scopeIds) : undefined,
),
)
.groupBy(schema.submission.userId, schema.submission.problemId),
db
.select({
userId: schema.submission.userId,
problemId: schema.submission.problemId,
first: min(schema.submission.createTime),
})
.from(schema.submission)
.where(
and(
inArray(schema.submission.result, accepted),
inArray(schema.submission.problemId, problemIds),
gte(schema.submission.createTime, start),
lte(schema.submission.createTime, end),
scopeIds ? inArray(schema.submission.userId, scopeIds) : undefined,
),
)
.groupBy(schema.submission.userId, schema.submission.problemId),
db
.select({
problemId: schema.submission.problemId,
time: schema.submission.createTime,
})
.from(schema.submission)
.where(
and(
eq(schema.submission.userId, user.id),
inArray(schema.submission.problemId, problemIds),
gte(schema.submission.createTime, start),
lte(schema.submission.createTime, end),
),
),
])
const byProblem = new Map(problems.map((item) => [item.problem.id, item]))
// 到首次通过为止提交了几次:只数首次 AC 那一刻(含)之前的提交
const firstAcTime = new Map(
firstAc.flatMap((item) =>
item.first ? ([[item.problemId, Date.parse(item.first)]] as const) : [],
),
)
const attemptsByProblem = new Map<number, number>()
for (const row of attemptRows) {
const deadline = firstAcTime.get(row.problemId)
if (deadline === undefined || Date.parse(row.time) > deadline) continue
attemptsByProblem.set(row.problemId, (attemptsByProblem.get(row.problemId) ?? 0) + 1)
}
function ranks(rows: typeof rankRows, problemId: number) {
return rows
.filter((item) => item.problemId === problemId)
.sort((a, b) => Date.parse(a.first ?? "") - Date.parse(b.first ?? "") || a.userId - b.userId)
}
const solved = firstAc
.flatMap((item) => {
const problem = byProblem.get(item.problemId)
if (!problem || !item.first) return []
const all = ranks(rankRows, item.problemId)
const period = ranks(periodRows, item.problemId)
const rank = all.findIndex((row) => row.userId === user.id) + 1 || null
const periodRank = period.findIndex((row) => row.userId === user.id) + 1 || null
return {
problem: {
title: problem.problem.title,
displayId: problem.problem.displayId,
contestTitle: problem.contestTitle ?? "",
contestId: problem.problem.contestId,
},
acTime: item.first,
rank,
acCount: all.length,
grade: grade(periodRank, period.length, all.length),
periodRank,
periodAcCount: period.length,
difficulty: difficultyNames[problem.problem.difficulty] ?? "中等",
attempts: attemptsByProblem.get(item.problemId) ?? 1,
} satisfies SolvedProblem
})
.sort((a, b) => Date.parse(a.acTime) - Date.parse(b.acTime))
return { solved, problems, scopeIds }
}
/** 分页版:只算这一页的题 */
export async function listSolved(
user: AuthUser,
start: string,
end: string,
limit: number,
offset: number,
) {
const [firstAc, totalRows] = await Promise.all([
firstAcQuery(user, start, end, limit, offset),
db
.select({ value: countDistinct(schema.submission.problemId) })
.from(schema.submission)
.where(
and(
eq(schema.submission.userId, user.id),
inArray(schema.submission.result, accepted),
gte(schema.submission.createTime, start),
lte(schema.submission.createTime, end),
),
),
])
const { solved } = await buildSolved(user, start, end, firstAc)
return {
results: solved,
total: totalRows[0]?.value ?? 0,
} satisfies SolvedList
}
export async function buildDetail(user: AuthUser, start: string, end: string) {
// 时间活跃度按**全部提交**统计,不是只按 AC。只看 AC 的话,一个学生两个月十来次
// 通过撒进 7×4 的格子里几乎全是空的,"高峰时段"根本看不出来。
// 星期和小时都按东八区取,和热力图同口径
const weekday =
sql<number>`extract(dow from ${localTime(schema.submission.createTime)})::int`.mapWith(Number)
const period =
sql<number>`floor(extract(hour from ${localTime(schema.submission.createTime)}) / 6)::int`.mapWith(
Number,
)
const activityRows = await db
.select({ weekday, period, value: count() })
.from(schema.submission)
.where(
and(
eq(schema.submission.userId, user.id),
gte(schema.submission.createTime, start),
lte(schema.submission.createTime, end),
),
)
.groupBy(weekday, period)
const activity = activityRows.map((row) => ({
weekday: row.weekday,
period: row.period,
count: row.value,
}))
// 区间内该用户的全部提交,一次拉回来喂两处:错题类型分布、每题到首次通过的尝试次数。
// 放在 problemIds 的空判断之前 —— 一道题都没做出来的学生,错题分布照样有意义
const submissions = await db
.select({
problemId: schema.submission.problemId,
time: schema.submission.createTime,
result: schema.submission.result,
})
.from(schema.submission)
.where(
and(
eq(schema.submission.userId, user.id),
gte(schema.submission.createTime, start),
lte(schema.submission.createTime, end),
),
)
const settledFail = (result: JudgeStatusValue) =>
!accepted.includes(result) && result !== JudgeStatus.PENDING && result !== JudgeStatus.JUDGING
const errorCounts = new Map<number, number>()
for (const row of submissions) {
if (!settledFail(row.result)) continue
errorCounts.set(row.result, (errorCounts.get(row.result) ?? 0) + 1)
}
const errors = [...errorCounts]
.map(([result, count]) => ({ result, count }))
.sort((a, b) => b.count - a.count || a.result - b.result)
const firstAc = await firstAcQuery(user, start, end)
const problemIds = firstAc.map((item) => item.problemId)
if (!problemIds.length)
return {
username: user.username,
className: user.className,
start,
end,
solvedCount: 0,
attempts: [],
flowcharts: [],
grade: "",
tags: {},
difficulty: {},
contestCount: 0,
activity,
errors,
rankScope: "global",
} satisfies AiDetail
const [{ solved, problems, scopeIds }, tagRows, flowRows] = await Promise.all([
buildSolved(user, start, end, firstAc),
db
.select({
problemId: schema.problemTags.problemId,
name: schema.problemTag.name,
})
.from(schema.problemTags)
.innerJoin(schema.problemTag, eq(schema.problemTags.problemtagId, schema.problemTag.id))
.where(inArray(schema.problemTags.problemId, problemIds)),
db
.select({
flow: schema.flowchartSubmission,
displayId: schema.problem.displayId,
title: schema.problem.title,
})
.from(schema.flowchartSubmission)
.innerJoin(schema.problem, eq(schema.flowchartSubmission.problemId, schema.problem.id))
.where(
and(
eq(schema.flowchartSubmission.userId, user.id),
eq(schema.flowchartSubmission.status, 2),
gte(schema.flowchartSubmission.createTime, start),
lte(schema.flowchartSubmission.createTime, end),
),
),
])
const tags: Record<string, number> = {}
for (const tag of tagRows) tags[tag.name] = (tags[tag.name] ?? 0) + 1
const topTags = Object.fromEntries(
Object.entries(tags)
.sort((a, b) => b[1] - a[1])
.slice(0, 5),
)
const difficulty: Record<string, number> = { 简单: 0, 中等: 0, 困难: 0 }
for (const item of problems) {
const name = difficultyNames[item.problem.difficulty] ?? "中等"
difficulty[name] = (difficulty[name] ?? 0) + 1
}
const flowGroups = new Map<string, typeof flowRows>()
for (const flow of flowRows)
flowGroups.set(flow.displayId, [...(flowGroups.get(flow.displayId) ?? []), flow])
const flowcharts = [...flowGroups]
.map(([displayId, rows]) => {
const scores = rows.flatMap((row) => row.flow.aiScore ?? [])
// 直接留住得分最高的那一次,等级读它。原来是拿 max 回头 find 分数相等的行 ——
// ai_score 是 double,相等比较本就不可靠;全是 null 时 max 退成 0,更是谁都匹配不上
const top = rows.reduce(
(best, row) => ((row.flow.aiScore ?? -1) > (best.flow.aiScore ?? -1) ? row : best),
rows[0]!,
)
return {
problemId: displayId,
problemTitle: rows[0]?.title ?? "",
submissionCount: rows.length,
bestScore: Math.max(0, top.flow.aiScore ?? 0),
bestGrade: top.flow.aiGrade ?? "",
latestSubmissionTime:
rows
.map((row) => row.flow.createTime)
.sort()
.at(-1) ?? start,
avgScore: rounded(
scores.length ? scores.reduce((sum, value) => sum + value, 0) / scores.length : 0,
0,
),
}
})
.sort((a, b) => b.latestSubmissionTime.localeCompare(a.latestSubmissionTime))
return {
username: user.username,
className: user.className,
start,
end,
flowcharts,
solvedCount: solved.length,
attempts: solved.map((item) => item.attempts),
grade: averageGrade(solved.map((item) => item.grade)),
tags: topTags,
difficulty,
contestCount: new Set(solved.flatMap((item) => item.problem.contestId ?? [])).size,
activity,
errors,
rankScope: scopeIds ? "class" : "global",
} satisfies AiDetail
}
export async function buildDuration(user: AuthUser, endText: string, duration: string) {
const config =
duration === "months:2"
? {
count: 8,
unit: "weeks",
rewind: (date: Date) => new Date(date.getTime() - 9 * 7 * 864e5),
advance: (date: Date) => new Date(date.getTime() + 7 * 864e5),
}
: duration === "months:6"
? {
count: 6,
unit: "months",
rewind: (date: Date) => shiftMonthsByCalendar(date, -7),
advance: (date: Date) => shiftMonthsByCalendar(date, 1),
}
: duration === "years:1"
? {
count: 12,
unit: "months",
rewind: (date: Date) => shiftMonthsByCalendar(date, -13),
advance: (date: Date) => shiftMonthsByCalendar(date, 1),
}
: {
count: 4,
unit: "weeks",
rewind: (date: Date) => new Date(date.getTime() - 5 * 7 * 864e5),
advance: (date: Date) => new Date(date.getTime() + 7 * 864e5),
}
// 先把 count 个时间桶算出来,再一条查询把整段区间的提交拉回来在内存里分桶。
// 以前是每个桶两条查询、桶之间还是串行的,一年 12 个桶就是 24 次往返。
// 相邻桶首尾相接、两端都是闭区间(end_i == start_{i+1}),落在边界上的提交
// 两个桶都算 —— 这是旧行为,照搬,不要「顺手」改成半开区间。
let cursor = config.rewind(new Date(endText))
const buckets: { start: Date; end: Date }[] = []
for (let index = 0; index < config.count; index++) {
const start = config.advance(cursor)
buckets.push({ start, end: config.advance(start) })
cursor = start
}
// 时间戳取 epoch 毫秒回来,比较在 JS 里做,和原来在 SQL 里比 timestamptz 等价,
// 不受 pg 那个「空格分隔 + +00 偏移」字符串格式能否被 Date.parse 认的影响
const rows = await db
.select({
time: sql<number>`extract(epoch from ${schema.submission.createTime}) * 1000`.mapWith(Number),
problemId: schema.submission.problemId,
result: schema.submission.result,
})
.from(schema.submission)
.where(
and(
eq(schema.submission.userId, user.id),
gte(schema.submission.createTime, buckets[0]!.start.toISOString()),
lte(schema.submission.createTime, buckets.at(-1)!.end.toISOString()),
),
)
// 每个桶的等级 = 桶内解出的每道题各算一个等级再取平均,排名按「同班同学在这个桶里
// 解出该题的先后」。和旧后端 OnlineJudge/ai/views/oj.py:484 一条一条对齐,包括这里
// 不传 reference(不打小规模折扣)—— 那个折扣只在 /ai/detail 那支用。
// 迁移时这里被写死成 `solved ? "B" : ""`,DurationChart 上那条等级折线因此恒定在 B。
const solvedIds = [
...new Set(rows.filter((row) => accepted.includes(row.result)).map((row) => row.problemId)),
]
const classUsers = user.className
? await db
.select({ id: schema.user.id })
.from(schema.user)
.where(eq(schema.user.className, user.className))
: []
const scopeIds = classUsers.length > 1 ? classUsers.map((item) => item.id) : null
const peers = solvedIds.length
? await db
.select({
time: sql<number>`extract(epoch from ${schema.submission.createTime}) * 1000`.mapWith(
Number,
),
userId: schema.submission.userId,
problemId: schema.submission.problemId,
})
.from(schema.submission)
.where(
and(
inArray(schema.submission.result, accepted),
inArray(schema.submission.problemId, solvedIds),
gte(schema.submission.createTime, buckets[0]!.start.toISOString()),
lte(schema.submission.createTime, buckets.at(-1)!.end.toISOString()),
scopeIds ? inArray(schema.submission.userId, scopeIds) : undefined,
),
)
: []
// 一次查回来在内存里按题分组再按桶切,别在循环里发查询:一年 12 个桶 × 几十道题
const peersByProblem = new Map<number, typeof peers>()
for (const row of peers)
peersByProblem.set(row.problemId, [...(peersByProblem.get(row.problemId) ?? []), row])
function bucketGrade(problemIds: number[], from: number, to: number) {
return averageGrade(
problemIds.map((problemId) => {
const firstAc = new Map<number, number>()
for (const row of peersByProblem.get(problemId) ?? []) {
if (row.time < from || row.time > to) continue
const seen = firstAc.get(row.userId)
if (seen === undefined || row.time < seen) firstAc.set(row.userId, row.time)
}
const ordered = [...firstAc].sort((a, b) => a[1] - b[1] || a[0] - b[0])
const rank = ordered.findIndex(([id]) => id === user.id) + 1 || null
return grade(rank, ordered.length)
}),
)
}
return buckets.map((bucket, index) => {
const from = bucket.start.getTime()
const to = bucket.end.getTime()
const inRange = rows.filter((row) => row.time >= from && row.time <= to)
const acceptedRows = inRange.filter((row) => accepted.includes(row.result))
const solved = [...new Set(acceptedRows.map((row) => row.problemId))]
return {
unit: config.unit,
index: config.count - 1 - index,
start: bucket.start.toISOString(),
end: bucket.end.toISOString(),
grade: solved.length ? bucketGrade(solved, from, to) : "",
problemCount: solved.length,
acceptedCount: acceptedRows.length,
submissionCount: inRange.length,
} satisfies DurationData
})
}