chore(格式): Prettier 统一到全仓,后端和契约一次性格式化
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原来只有 `apps/web` 在 Prettier 下(配置在 `apps/web/.prettierrc.toml`、脚本在
web 的 package.json),后端和契约从来没格式化过 —— 手写在 100 列上下,`db/schema.ts`
还是 drizzle-kit pull 留下的 tab 缩进。两套口径分叉久了,跨端改一处就得记着「这边
什么风格」。

- 配置搬到根目录 `.prettierrc.toml`,内容不变(`semi=false`,其余全默认,
  printWidth 80 —— 和前端已有的格式一致,不另立一套宽度);
- 脚本统一成根目录 `bun run fmt`,覆盖 `apps/*/src`、`apps/web/tests` 和两个构建
  配置;web 自己那份 `fmt` 和重复的 prettier 依赖删掉;
- `.prettierignore` 挡掉两类不该碰的:drizzle-kit 生成的 `src/db/meta/` 结构快照
  (它是 db:generate 的比对输入,只该由 drizzle-kit 写)、unplugin 每次 dev 都会
  重写的 `auto-imports.d.ts` / `components.d.ts`;
- 全量跑了一遍。纯格式,无行为改动:api typecheck / check:routes / check:ast、
  前端 type-check 全过,起 api 打了接口确认正常。前端这 39 个文件的小改动是
  prettier 版本漂移(类型断言的换行口径变了),不是新配置带来的。

Co-Authored-By: Claude Opus 5 <noreply@anthropic.com>
This commit is contained in:
xuyueandClaude Opus 5 committed 2026-09-16 08:27:34 -06:00
1 parent e600fd24cf
commit ed56a209ea
122 files changed
+10557 -4843

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@@ -6,8 +6,13 @@ import { objectValue } from "../routes/helpers"
type BadgeRow = typeof schema.problemsetBadge.$inferSelect
type ProgressRow = typeof schema.problemsetProgress.$inferSelect
type ProblemLink = { problemId: number; score: number; isRequired: boolean }
type BadgeCheck = Pick<ProgressRow,
"completedProblemsCount" | "totalProblemsCount" | "totalScore" | "progressDetail">
type BadgeCheck = Pick<
ProgressRow,
| "completedProblemsCount"
| "totalProblemsCount"
| "totalScore"
| "progressDetail"
>
/**
* 题单进度的唯一算法:学生做出一道题后的增量更新、后台改动题目后的批量重算,都走这一份。
@@ -24,7 +29,9 @@ export function computeProgress(
previousCompleteTime: string | null,
now = new Date().toISOString(),
) {
const scoreByProblem = new Map(links.map((link) => [String(link.problemId), link.score]))
const scoreByProblem = new Map(
links.map((link) => [String(link.problemId), link.score]),
)
// 已经移出题单的题目要从 detail 里剔掉,留着它 completed 就会比实际做出的题还多
const kept: Record<string, unknown> = {}
let totalScore = 0
@@ -44,7 +51,9 @@ export function computeProgress(
const required = links.filter((link) => link.isRequired)
const graded = required.length ? required : links
const gradedKeys = new Set(graded.map((link) => String(link.problemId)))
const completed = Object.keys(kept).filter((key) => gradedKeys.has(key)).length
const completed = Object.keys(kept).filter((key) =>
gradedKeys.has(key),
).length
const total = graded.length
// total > 0 这个前提不能省:0 === 0 同样成立,没有题目的题单会让人一加入就算「完成」,
// 还会写下 complete_time、计进「完成题单数」成就,而且后面补上题目也不会自愈。
@@ -55,7 +64,8 @@ export function computeProgress(
completedProblemsCount: completed,
totalScore,
// 乘 10000 四舍五入再除 100,保留两位小数
progressPercentage: total > 0 ? Math.round((completed / total) * 10000) / 100 : 0,
progressPercentage:
total > 0 ? Math.round((completed / total) * 10000) / 100 : 0,
isCompleted,
// 只设不清,语义是「曾经完成于」,对齐旧栈 problemset/models.py:218。
//
@@ -78,7 +88,8 @@ async function writeProgress(rows: ProgressWrite[]) {
for (let start = 0; start < rows.length; start += 1000) {
const chunk = rows.slice(start, start + 1000)
const values = sql.join(
chunk.map((row) => sql`(
chunk.map(
(row) => sql`(
${row.id}::bigint,
${JSON.stringify(row.progressDetail)}::jsonb,
${row.totalProblemsCount}::int,
@@ -87,7 +98,8 @@ async function writeProgress(rows: ProgressWrite[]) {
${row.progressPercentage}::double precision,
${row.isCompleted}::boolean,
${row.completeTime}::timestamptz
)`),
)`,
),
sql`, `,
)
await db.execute(sql`
@@ -118,13 +130,19 @@ async function writeProgress(rows: ProgressWrite[]) {
*/
export function eligibleForBadge(badge: BadgeRow, progress: BadgeCheck) {
if (badge.conditionType === "all_problems") {
return progress.totalProblemsCount > 0 &&
return (
progress.totalProblemsCount > 0 &&
progress.completedProblemsCount === progress.totalProblemsCount
)
}
if (badge.conditionType === "problem_count") {
return Object.keys(objectValue(progress.progressDetail)).length >= badge.conditionValue
return (
Object.keys(objectValue(progress.progressDetail)).length >=
badge.conditionValue
)
}
if (badge.conditionType === "score") return progress.totalScore >= badge.conditionValue
if (badge.conditionType === "score")
return progress.totalScore >= badge.conditionValue
return false
}
@@ -136,26 +154,45 @@ export function eligibleForBadge(badge: BadgeRow, progress: BadgeCheck) {
* 调用方手里已经有最新的进度时把它传进来(`known`),省掉一次回表;
* 更要紧的是别用刚写完库之前的旧值去判定。
*/
export async function recalculateBadge(badge: BadgeRow, known?: (BadgeCheck & { userId: number })[]) {
const progresses = known ?? await db.select().from(schema.problemsetProgress)
.where(eq(schema.problemsetProgress.problemsetId, badge.problemsetId))
const eligibleIds = progresses.filter((item) => eligibleForBadge(badge, item)).map((item) => item.userId)
export async function recalculateBadge(
badge: BadgeRow,
known?: (BadgeCheck & { userId: number })[],
) {
const progresses =
known ??
(await db
.select()
.from(schema.problemsetProgress)
.where(eq(schema.problemsetProgress.problemsetId, badge.problemsetId)))
const eligibleIds = progresses
.filter((item) => eligibleForBadge(badge, item))
.map((item) => item.userId)
await db.transaction(async (tx) => {
await tx.delete(schema.userBadge).where(and(
eq(schema.userBadge.badgeId, badge.id),
eligibleIds.length ? notInArray(schema.userBadge.userId, eligibleIds) : undefined,
))
await tx
.delete(schema.userBadge)
.where(
and(
eq(schema.userBadge.badgeId, badge.id),
eligibleIds.length
? notInArray(schema.userBadge.userId, eligibleIds)
: undefined,
),
)
if (!eligibleIds.length) return
const existing = await tx.select({ userId: schema.userBadge.userId }).from(schema.userBadge)
const existing = await tx
.select({ userId: schema.userBadge.userId })
.from(schema.userBadge)
.where(eq(schema.userBadge.badgeId, badge.id))
const have = new Set(existing.map((item) => item.userId))
const missing = eligibleIds.filter((id) => !have.has(id))
if (missing.length) {
await tx.insert(schema.userBadge).values(missing.map((userId) => ({
userId,
badgeId: badge.id,
earnedTime: new Date().toISOString(),
})))
await tx.insert(schema.userBadge).values(
missing.map((userId) => ({
userId,
badgeId: badge.id,
earnedTime: new Date().toISOString(),
})),
)
}
})
}
@@ -174,20 +211,32 @@ export async function recalculateBadge(badge: BadgeRow, known?: (BadgeCheck & {
*/
export async function resyncProgress(problemsetId: number) {
const [links, progresses, badges] = await Promise.all([
db.select({
problemId: schema.problemsetProblem.problemId,
score: schema.problemsetProblem.score,
isRequired: schema.problemsetProblem.isRequired,
}).from(schema.problemsetProblem).where(eq(schema.problemsetProblem.problemsetId, problemsetId)),
db.select().from(schema.problemsetProgress)
db
.select({
problemId: schema.problemsetProblem.problemId,
score: schema.problemsetProblem.score,
isRequired: schema.problemsetProblem.isRequired,
})
.from(schema.problemsetProblem)
.where(eq(schema.problemsetProblem.problemsetId, problemsetId)),
db
.select()
.from(schema.problemsetProgress)
.where(eq(schema.problemsetProgress.problemsetId, problemsetId)),
db.select().from(schema.problemsetBadge)
db
.select()
.from(schema.problemsetBadge)
.where(eq(schema.problemsetBadge.problemsetId, problemsetId)),
])
const now = new Date().toISOString()
const updated = progresses.map((progress) => ({
...progress,
...computeProgress(objectValue(progress.progressDetail), links, progress.completeTime, now),
...computeProgress(
objectValue(progress.progressDetail),
links,
progress.completeTime,
now,
),
}))
if (updated.length) await writeProgress(updated)
for (const badge of badges) await recalculateBadge(badge, updated)
@@ -214,59 +263,93 @@ export async function recordSolvedProblem(
const joined = await db
.select({ problemsetId: schema.problemsetProgress.problemsetId })
.from(schema.problemsetProgress)
.innerJoin(schema.problemsetProblem, and(
eq(schema.problemsetProblem.problemsetId, schema.problemsetProgress.problemsetId),
eq(schema.problemsetProblem.problemId, problemId),
))
.innerJoin(
schema.problemsetProblem,
and(
eq(
schema.problemsetProblem.problemsetId,
schema.problemsetProgress.problemsetId,
),
eq(schema.problemsetProblem.problemId, problemId),
),
)
.where(eq(schema.problemsetProgress.userId, userId))
const earned: BadgeRow[] = []
let updated = 0
for (const { problemsetId } of joined) {
const hits = await db.transaction(async (tx) => {
const [progress] = await tx.select().from(schema.problemsetProgress).where(and(
eq(schema.problemsetProgress.problemsetId, problemsetId),
eq(schema.problemsetProgress.userId, userId),
)).for("update").limit(1)
const [progress] = await tx
.select()
.from(schema.problemsetProgress)
.where(
and(
eq(schema.problemsetProgress.problemsetId, problemsetId),
eq(schema.problemsetProgress.userId, userId),
),
)
.for("update")
.limit(1)
if (!progress) return []
// 提交记录先补上,即使这道题早就记过 —— 老数据里有记了进度没记提交的行
const [existing] = await tx.select({ id: schema.problemsetSubmission.id })
.from(schema.problemsetSubmission).where(and(
eq(schema.problemsetSubmission.problemsetId, problemsetId),
eq(schema.problemsetSubmission.userId, userId),
eq(schema.problemsetSubmission.problemId, problemId),
)).limit(1)
const [existing] = await tx
.select({ id: schema.problemsetSubmission.id })
.from(schema.problemsetSubmission)
.where(
and(
eq(schema.problemsetSubmission.problemsetId, problemsetId),
eq(schema.problemsetSubmission.userId, userId),
eq(schema.problemsetSubmission.problemId, problemId),
),
)
.limit(1)
if (!existing) {
await tx.insert(schema.problemsetSubmission)
await tx
.insert(schema.problemsetSubmission)
.values({ problemsetId, userId, submissionId, problemId })
}
const detail = objectValue(progress.progressDetail)
if (String(problemId) in detail) return []
const links = await tx.select({
problemId: schema.problemsetProblem.problemId,
score: schema.problemsetProblem.score,
isRequired: schema.problemsetProblem.isRequired,
}).from(schema.problemsetProblem)
const links = await tx
.select({
problemId: schema.problemsetProblem.problemId,
score: schema.problemsetProblem.score,
isRequired: schema.problemsetProblem.isRequired,
})
.from(schema.problemsetProblem)
.where(eq(schema.problemsetProblem.problemsetId, problemsetId))
const link = links.find((item) => item.problemId === problemId)
if (!link) return []
detail[String(problemId)] = { score: link.score, submit_time: solvedAt }
const update = computeProgress(detail, links, progress.completeTime)
await tx.update(schema.problemsetProgress).set(update)
await tx
.update(schema.problemsetProgress)
.set(update)
.where(eq(schema.problemsetProgress.id, progress.id))
updated += 1
const badges = await tx.select().from(schema.problemsetBadge)
const badges = await tx
.select()
.from(schema.problemsetBadge)
.where(eq(schema.problemsetBadge.problemsetId, problemsetId))
const eligible = badges.filter((badge) => eligibleForBadge(badge, { ...progress, ...update }))
const eligible = badges.filter((badge) =>
eligibleForBadge(badge, { ...progress, ...update }),
)
if (eligible.length === 0) return []
// 达标的奖章一次插完,冲突忽略后 returning 回来的就是这次真拿到的
const inserted = await tx.insert(schema.userBadge).values(eligible.map((badge) => ({
userId,
badgeId: badge.id,
earnedTime: new Date().toISOString(),
}))).onConflictDoNothing({ target: [schema.userBadge.badgeId, schema.userBadge.userId] })
const inserted = await tx
.insert(schema.userBadge)
.values(
eligible.map((badge) => ({
userId,
badgeId: badge.id,
earnedTime: new Date().toISOString(),
})),
)
.onConflictDoNothing({
target: [schema.userBadge.badgeId, schema.userBadge.userId],
})
.returning({ badgeId: schema.userBadge.badgeId })
const ids = new Set(inserted.map((row) => row.badgeId))
return eligible.filter((badge) => ids.has(badge.id))