原来只有 `apps/web` 在 Prettier 下(配置在 `apps/web/.prettierrc.toml`、脚本在 web 的 package.json),后端和契约从来没格式化过 —— 手写在 100 列上下,`db/schema.ts` 还是 drizzle-kit pull 留下的 tab 缩进。两套口径分叉久了,跨端改一处就得记着「这边 什么风格」。 - 配置搬到根目录 `.prettierrc.toml`,内容不变(`semi=false`,其余全默认, printWidth 80 —— 和前端已有的格式一致,不另立一套宽度); - 脚本统一成根目录 `bun run fmt`,覆盖 `apps/*/src`、`apps/web/tests` 和两个构建 配置;web 自己那份 `fmt` 和重复的 prettier 依赖删掉; - `.prettierignore` 挡掉两类不该碰的:drizzle-kit 生成的 `src/db/meta/` 结构快照 (它是 db:generate 的比对输入,只该由 drizzle-kit 写)、unplugin 每次 dev 都会 重写的 `auto-imports.d.ts` / `components.d.ts`; - 全量跑了一遍。纯格式,无行为改动:api typecheck / check:routes / check:ast、 前端 type-check 全过,起 api 打了接口确认正常。前端这 39 个文件的小改动是 prettier 版本漂移(类型断言的换行口径变了),不是新配置带来的。 Co-Authored-By: Claude Opus 5 <noreply@anthropic.com>
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@@ -6,8 +6,13 @@ import { objectValue } from "../routes/helpers"
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type BadgeRow = typeof schema.problemsetBadge.$inferSelect
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type ProgressRow = typeof schema.problemsetProgress.$inferSelect
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type ProblemLink = { problemId: number; score: number; isRequired: boolean }
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type BadgeCheck = Pick<ProgressRow,
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"completedProblemsCount" | "totalProblemsCount" | "totalScore" | "progressDetail">
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type BadgeCheck = Pick<
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ProgressRow,
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| "completedProblemsCount"
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| "totalProblemsCount"
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| "totalScore"
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| "progressDetail"
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>
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/**
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* 题单进度的唯一算法:学生做出一道题后的增量更新、后台改动题目后的批量重算,都走这一份。
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@@ -24,7 +29,9 @@ export function computeProgress(
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previousCompleteTime: string | null,
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now = new Date().toISOString(),
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) {
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const scoreByProblem = new Map(links.map((link) => [String(link.problemId), link.score]))
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const scoreByProblem = new Map(
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links.map((link) => [String(link.problemId), link.score]),
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)
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// 已经移出题单的题目要从 detail 里剔掉,留着它 completed 就会比实际做出的题还多
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const kept: Record<string, unknown> = {}
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let totalScore = 0
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@@ -44,7 +51,9 @@ export function computeProgress(
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const required = links.filter((link) => link.isRequired)
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const graded = required.length ? required : links
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const gradedKeys = new Set(graded.map((link) => String(link.problemId)))
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const completed = Object.keys(kept).filter((key) => gradedKeys.has(key)).length
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const completed = Object.keys(kept).filter((key) =>
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gradedKeys.has(key),
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).length
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const total = graded.length
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// total > 0 这个前提不能省:0 === 0 同样成立,没有题目的题单会让人一加入就算「完成」,
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// 还会写下 complete_time、计进「完成题单数」成就,而且后面补上题目也不会自愈。
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@@ -55,7 +64,8 @@ export function computeProgress(
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completedProblemsCount: completed,
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totalScore,
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// 乘 10000 四舍五入再除 100,保留两位小数
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progressPercentage: total > 0 ? Math.round((completed / total) * 10000) / 100 : 0,
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progressPercentage:
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total > 0 ? Math.round((completed / total) * 10000) / 100 : 0,
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isCompleted,
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// 只设不清,语义是「曾经完成于」,对齐旧栈 problemset/models.py:218。
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//
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@@ -78,7 +88,8 @@ async function writeProgress(rows: ProgressWrite[]) {
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for (let start = 0; start < rows.length; start += 1000) {
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const chunk = rows.slice(start, start + 1000)
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const values = sql.join(
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chunk.map((row) => sql`(
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chunk.map(
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(row) => sql`(
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${row.id}::bigint,
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${JSON.stringify(row.progressDetail)}::jsonb,
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${row.totalProblemsCount}::int,
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@@ -87,7 +98,8 @@ async function writeProgress(rows: ProgressWrite[]) {
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${row.progressPercentage}::double precision,
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${row.isCompleted}::boolean,
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${row.completeTime}::timestamptz
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)`),
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)`,
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),
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sql`, `,
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)
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await db.execute(sql`
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@@ -118,13 +130,19 @@ async function writeProgress(rows: ProgressWrite[]) {
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*/
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export function eligibleForBadge(badge: BadgeRow, progress: BadgeCheck) {
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if (badge.conditionType === "all_problems") {
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return progress.totalProblemsCount > 0 &&
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return (
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progress.totalProblemsCount > 0 &&
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progress.completedProblemsCount === progress.totalProblemsCount
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)
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}
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if (badge.conditionType === "problem_count") {
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return Object.keys(objectValue(progress.progressDetail)).length >= badge.conditionValue
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return (
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Object.keys(objectValue(progress.progressDetail)).length >=
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badge.conditionValue
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)
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}
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if (badge.conditionType === "score") return progress.totalScore >= badge.conditionValue
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if (badge.conditionType === "score")
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return progress.totalScore >= badge.conditionValue
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return false
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}
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@@ -136,26 +154,45 @@ export function eligibleForBadge(badge: BadgeRow, progress: BadgeCheck) {
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* 调用方手里已经有最新的进度时把它传进来(`known`),省掉一次回表;
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* 更要紧的是别用刚写完库之前的旧值去判定。
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*/
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export async function recalculateBadge(badge: BadgeRow, known?: (BadgeCheck & { userId: number })[]) {
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const progresses = known ?? await db.select().from(schema.problemsetProgress)
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.where(eq(schema.problemsetProgress.problemsetId, badge.problemsetId))
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const eligibleIds = progresses.filter((item) => eligibleForBadge(badge, item)).map((item) => item.userId)
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export async function recalculateBadge(
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badge: BadgeRow,
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known?: (BadgeCheck & { userId: number })[],
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) {
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const progresses =
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known ??
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(await db
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.select()
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.from(schema.problemsetProgress)
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.where(eq(schema.problemsetProgress.problemsetId, badge.problemsetId)))
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const eligibleIds = progresses
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.filter((item) => eligibleForBadge(badge, item))
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.map((item) => item.userId)
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await db.transaction(async (tx) => {
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await tx.delete(schema.userBadge).where(and(
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eq(schema.userBadge.badgeId, badge.id),
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eligibleIds.length ? notInArray(schema.userBadge.userId, eligibleIds) : undefined,
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))
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await tx
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.delete(schema.userBadge)
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.where(
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and(
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eq(schema.userBadge.badgeId, badge.id),
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eligibleIds.length
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? notInArray(schema.userBadge.userId, eligibleIds)
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: undefined,
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),
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)
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if (!eligibleIds.length) return
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const existing = await tx.select({ userId: schema.userBadge.userId }).from(schema.userBadge)
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const existing = await tx
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.select({ userId: schema.userBadge.userId })
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.from(schema.userBadge)
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.where(eq(schema.userBadge.badgeId, badge.id))
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const have = new Set(existing.map((item) => item.userId))
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const missing = eligibleIds.filter((id) => !have.has(id))
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if (missing.length) {
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await tx.insert(schema.userBadge).values(missing.map((userId) => ({
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userId,
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badgeId: badge.id,
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earnedTime: new Date().toISOString(),
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})))
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await tx.insert(schema.userBadge).values(
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missing.map((userId) => ({
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userId,
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badgeId: badge.id,
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earnedTime: new Date().toISOString(),
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})),
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)
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}
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})
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}
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@@ -174,20 +211,32 @@ export async function recalculateBadge(badge: BadgeRow, known?: (BadgeCheck & {
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*/
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export async function resyncProgress(problemsetId: number) {
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const [links, progresses, badges] = await Promise.all([
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db.select({
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problemId: schema.problemsetProblem.problemId,
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score: schema.problemsetProblem.score,
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isRequired: schema.problemsetProblem.isRequired,
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}).from(schema.problemsetProblem).where(eq(schema.problemsetProblem.problemsetId, problemsetId)),
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db.select().from(schema.problemsetProgress)
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db
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.select({
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problemId: schema.problemsetProblem.problemId,
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score: schema.problemsetProblem.score,
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isRequired: schema.problemsetProblem.isRequired,
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})
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.from(schema.problemsetProblem)
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.where(eq(schema.problemsetProblem.problemsetId, problemsetId)),
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db
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.select()
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.from(schema.problemsetProgress)
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.where(eq(schema.problemsetProgress.problemsetId, problemsetId)),
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db.select().from(schema.problemsetBadge)
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db
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.select()
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.from(schema.problemsetBadge)
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.where(eq(schema.problemsetBadge.problemsetId, problemsetId)),
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])
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const now = new Date().toISOString()
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const updated = progresses.map((progress) => ({
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...progress,
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...computeProgress(objectValue(progress.progressDetail), links, progress.completeTime, now),
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...computeProgress(
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objectValue(progress.progressDetail),
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links,
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progress.completeTime,
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now,
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),
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}))
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if (updated.length) await writeProgress(updated)
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for (const badge of badges) await recalculateBadge(badge, updated)
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@@ -214,59 +263,93 @@ export async function recordSolvedProblem(
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const joined = await db
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.select({ problemsetId: schema.problemsetProgress.problemsetId })
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.from(schema.problemsetProgress)
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.innerJoin(schema.problemsetProblem, and(
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eq(schema.problemsetProblem.problemsetId, schema.problemsetProgress.problemsetId),
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eq(schema.problemsetProblem.problemId, problemId),
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))
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.innerJoin(
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schema.problemsetProblem,
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and(
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eq(
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schema.problemsetProblem.problemsetId,
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schema.problemsetProgress.problemsetId,
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),
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eq(schema.problemsetProblem.problemId, problemId),
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),
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)
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.where(eq(schema.problemsetProgress.userId, userId))
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const earned: BadgeRow[] = []
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let updated = 0
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for (const { problemsetId } of joined) {
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const hits = await db.transaction(async (tx) => {
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const [progress] = await tx.select().from(schema.problemsetProgress).where(and(
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eq(schema.problemsetProgress.problemsetId, problemsetId),
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eq(schema.problemsetProgress.userId, userId),
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)).for("update").limit(1)
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const [progress] = await tx
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.select()
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.from(schema.problemsetProgress)
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.where(
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and(
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eq(schema.problemsetProgress.problemsetId, problemsetId),
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eq(schema.problemsetProgress.userId, userId),
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),
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)
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.for("update")
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.limit(1)
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if (!progress) return []
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// 提交记录先补上,即使这道题早就记过 —— 老数据里有记了进度没记提交的行
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const [existing] = await tx.select({ id: schema.problemsetSubmission.id })
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.from(schema.problemsetSubmission).where(and(
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eq(schema.problemsetSubmission.problemsetId, problemsetId),
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eq(schema.problemsetSubmission.userId, userId),
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eq(schema.problemsetSubmission.problemId, problemId),
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)).limit(1)
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const [existing] = await tx
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.select({ id: schema.problemsetSubmission.id })
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.from(schema.problemsetSubmission)
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.where(
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and(
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eq(schema.problemsetSubmission.problemsetId, problemsetId),
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eq(schema.problemsetSubmission.userId, userId),
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eq(schema.problemsetSubmission.problemId, problemId),
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),
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)
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.limit(1)
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if (!existing) {
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await tx.insert(schema.problemsetSubmission)
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await tx
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.insert(schema.problemsetSubmission)
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.values({ problemsetId, userId, submissionId, problemId })
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}
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const detail = objectValue(progress.progressDetail)
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if (String(problemId) in detail) return []
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const links = await tx.select({
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problemId: schema.problemsetProblem.problemId,
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score: schema.problemsetProblem.score,
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isRequired: schema.problemsetProblem.isRequired,
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}).from(schema.problemsetProblem)
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const links = await tx
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.select({
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problemId: schema.problemsetProblem.problemId,
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score: schema.problemsetProblem.score,
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isRequired: schema.problemsetProblem.isRequired,
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})
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.from(schema.problemsetProblem)
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.where(eq(schema.problemsetProblem.problemsetId, problemsetId))
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const link = links.find((item) => item.problemId === problemId)
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if (!link) return []
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detail[String(problemId)] = { score: link.score, submit_time: solvedAt }
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const update = computeProgress(detail, links, progress.completeTime)
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await tx.update(schema.problemsetProgress).set(update)
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await tx
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.update(schema.problemsetProgress)
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.set(update)
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.where(eq(schema.problemsetProgress.id, progress.id))
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updated += 1
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const badges = await tx.select().from(schema.problemsetBadge)
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const badges = await tx
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.select()
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.from(schema.problemsetBadge)
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.where(eq(schema.problemsetBadge.problemsetId, problemsetId))
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const eligible = badges.filter((badge) => eligibleForBadge(badge, { ...progress, ...update }))
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const eligible = badges.filter((badge) =>
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eligibleForBadge(badge, { ...progress, ...update }),
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)
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if (eligible.length === 0) return []
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// 达标的奖章一次插完,冲突忽略后 returning 回来的就是这次真拿到的
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const inserted = await tx.insert(schema.userBadge).values(eligible.map((badge) => ({
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userId,
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badgeId: badge.id,
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earnedTime: new Date().toISOString(),
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}))).onConflictDoNothing({ target: [schema.userBadge.badgeId, schema.userBadge.userId] })
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const inserted = await tx
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.insert(schema.userBadge)
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.values(
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eligible.map((badge) => ({
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userId,
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badgeId: badge.id,
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earnedTime: new Date().toISOString(),
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})),
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)
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.onConflictDoNothing({
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target: [schema.userBadge.badgeId, schema.userBadge.userId],
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})
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.returning({ badgeId: schema.userBadge.badgeId })
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const ids = new Set(inserted.map((row) => row.badgeId))
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return eligible.filter((badge) => ids.has(badge.id))
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