refactor(提交): 教师统计路由拆出 submission-statistics.ts,check:routes 支持嵌套挂载
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- submission.ts 1416 行降到 751 行;统计三条路由拆成子路由,挂在原位置, 仍排在 /submissions/:id 之前 - check-route-shadowing 原来只认 index.ts 直接挂载,拆分后漏检 3 条(178→175); 现在按挂载位置展开嵌套的 .route(),恢复 178 条、无遮蔽 Co-Authored-By: Claude Sonnet 5 <noreply@anthropic.com>
This commit is contained in:
704
apps/api/src/routes/submission-statistics.ts
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704
apps/api/src/routes/submission-statistics.ts
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/**
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* 教师统计:今日提交分布、按学生/题目的统计面板、展开行的提交明细。
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*
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* 从 submission.ts 拆出来的一整块。**挂载位置不能动**:submission.ts 在原位置
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* `route("/", submissionStatisticsRoutes)`,必须排在 `/submissions/:id` 之前,
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* 否则 `/submissions/statistics` 会被当成 id 吞掉(Hono 按注册顺序匹配)。
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*/
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import {
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type SubmissionStatistics,
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type SubmissionStatisticsItems,
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type TodaySubmissionStatistics,
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} from "@oj2/contract"
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import {
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and,
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count,
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desc,
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eq,
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ilike,
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inArray,
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isNull,
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or,
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sql,
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type SQL,
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} from "drizzle-orm"
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import { Hono } from "hono"
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import { optionalAuth, requireTeacher } from "../auth/middleware"
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import type { AuthUser } from "../auth/session"
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import { db, schema } from "../db"
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import { failure, success } from "../http"
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import {
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JudgeStatus,
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UNJUDGED_RESULTS,
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type JudgeStatusValue,
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} from "../judge/status"
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import { type ContestEnv } from "../services/contest"
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import { getBooleanOption } from "../services/options"
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import { localTime, todayStart } from "../time"
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import { isAdminRole, matchedUsers, rounded, stripClassPrefix } from "./helpers"
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export const submissionStatisticsRoutes = new Hono<ContestEnv>()
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const ACCEPTED_RESULTS = [JudgeStatus.ACCEPTED, JudgeStatus.AST_CHECK_FAILED]
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/** 正确率。分母是判完的条数,一条都还没判完时给 0 而不是 NaN */
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function judgedRate(accepted: number, judged: number) {
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return judged > 0 ? rounded((accepted / judged) * 100) : 0
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}
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/**
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* 「今日提交数」标签点开的统计。**公开、只出聚合数**(没有用户名、没有代码,
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* 热门题只算公开可见的题),口径和那颗标签一致:东八区今天 + 非比赛提交。
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*
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* 按钟点切用 `localTime()`,不能写 `extract(hour from create_time)` ——
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* 后者按数据库会话时区算,容器是 UTC,整张分布图会整体左移 8 小时。
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*/
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submissionStatisticsRoutes.get(
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"/submissions/today-statistics",
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optionalAuth,
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async (c) => {
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/**
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* 「提交列表对学生全开」关掉时(考试那种场合)不给热门题这张表 —— 总数、正确率
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* 这些聚合数原本就从公开的 today-count 看得出来,但「哪几道题在被刷」已经贴近
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* 提交列表本身的内容了,得跟着同一个开关走。数字照给,不然标签说 21、弹框说 0。
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*/
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const showProblems =
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(await getBooleanOption("submission_list_show_all", true)) ||
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isAdminRole(c.get("user"))
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const where = and(
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isNull(schema.submission.contestId),
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sql`${schema.submission.createTime} >= ${todayStart()}`,
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)
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const acceptedFilter = sql`count(*) filter (where ${inArray(schema.submission.result, ACCEPTED_RESULTS)})`
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const judgingFilter = sql`count(*) filter (where ${inArray(schema.submission.result, UNJUDGED_RESULTS)})`
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const hour = sql<number>`extract(hour from ${localTime(schema.submission.createTime)})::int`
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const [[totals], hourRows, languageRows, resultRows, problemRows] =
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await Promise.all([
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db
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.select({
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total: count(),
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accepted: acceptedFilter.mapWith(Number),
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judging: judgingFilter.mapWith(Number),
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userCount:
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sql<number>`count(distinct ${schema.submission.userId})`.mapWith(
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Number,
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),
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})
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.from(schema.submission)
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.where(where),
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db
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.select({ hour, value: count() })
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.from(schema.submission)
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.where(where)
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.groupBy(hour),
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db
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.select({ language: schema.submission.language, value: count() })
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.from(schema.submission)
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.where(where)
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.groupBy(schema.submission.language)
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.orderBy(desc(count())),
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db
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.select({ result: schema.submission.result, value: count() })
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.from(schema.submission)
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.where(where)
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.groupBy(schema.submission.result)
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.orderBy(desc(count())),
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showProblems
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? db
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.select({
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displayId: schema.problem.displayId,
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title: schema.problem.title,
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value: count(),
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accepted: acceptedFilter.mapWith(Number),
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})
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.from(schema.submission)
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.innerJoin(
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schema.problem,
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eq(schema.problem.id, schema.submission.problemId),
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)
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// 隐藏题目不出现在这张表里:接口不需要登录,标题本身就是不该外露的东西
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.where(and(where, eq(schema.problem.visible, true)))
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.groupBy(
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schema.problem.id,
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schema.problem.displayId,
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schema.problem.title,
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)
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.orderBy(desc(count()))
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.limit(10)
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: [],
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])
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const total = totals?.total ?? 0
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const judging = totals?.judging ?? 0
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const hours = Array.from({ length: 24 }, () => 0)
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for (const row of hourRows) hours[row.hour] = row.value
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return success(c, {
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total,
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accepted: totals?.accepted ?? 0,
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judging,
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correctRate: judgedRate(totals?.accepted ?? 0, total - judging),
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userCount: totals?.userCount ?? 0,
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hours,
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languages: languageRows.map((row) => ({
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language: row.language,
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count: row.value,
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})),
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results: resultRows.map((row) => ({
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result: row.result,
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count: row.value,
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})),
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problems: problemRows.map((row) => ({
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problem: row.displayId,
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problemTitle: row.title,
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count: row.value,
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acceptedCount: row.accepted,
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})),
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} satisfies TodaySubmissionStatistics)
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},
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)
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/**
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* 统计接口共用的时间窗解析。旧后端 `end` 必填、`start` 可选(不给就是「全部时段」)。
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*/
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function statisticsRange(c: {
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req: { query(name: string): string | undefined }
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}) {
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const end = c.req.query("end")?.trim()
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if (!end) return null
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const start = c.req.query("start")?.trim()
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return { start: start || null, end }
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}
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/** 一次最多查几道题。课堂上一节课布置三五道,20 是留足了余量的上限 */
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const STATISTICS_MAX_PROBLEMS = 20
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/**
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* 题号框允许一次填几道:`1001,1005,1010`。中英文逗号、空格、分号都当分隔符 ——
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* 老师在投影前手敲,不该因为打了个全角逗号就查不出来。
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*/
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function parseDisplayIds(raw: string) {
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const seen = new Set<string>()
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const ids: string[] = []
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for (const part of raw.split(/[,,;;\s]+/)) {
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const id = part.trim()
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if (!id) continue
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const key = id.toLowerCase()
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if (seen.has(key)) continue
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seen.add(key)
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ids.push(id)
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}
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return ids
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}
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/**
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* 按题号(展示用的 _id)定位公开题目。**有一个找不到就整体报错**,不退化成「全部题目」——
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* 否则教师打错一个字就会看到全站数据还以为是这几道题的。
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*/
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async function findPublicProblemsByDisplayIds(displayIds: string[]) {
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const lowered = displayIds.map((id) => id.toLowerCase())
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const rows = await db
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.select({ id: schema.problem.id, displayId: schema.problem.displayId })
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.from(schema.problem)
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.where(
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and(
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inArray(sql`lower(${schema.problem.displayId})`, lowered),
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isNull(schema.problem.contestId),
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eq(schema.problem.visible, true),
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),
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)
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const found = new Set(rows.map((row) => row.displayId.toLowerCase()))
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const missing = displayIds.find((id) => !found.has(id.toLowerCase()))
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return { ids: rows.map((row) => row.id), missing: missing ?? null }
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}
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/**
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* 展开行一次只看一个人(表格的 updateExpandedRowKeys 只留最后一个 key),所以明细
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* **按需拉**,不再随统计一起下发。
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*
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* 原来是随 data 一起给所有人各带一份:生产快照实测,「全部时段 + 不填条件」要搬
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* 49108 行(最早那版不截断是 105631 行),而其中真正被人看到的最多一个人的那几十条。
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*/
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const STATISTICS_ITEMS_LIMIT = 200
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/** 错误摘要截断长度。编译错误能刷几十行,弹层里放不下,也没必要 */
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const FAILURE_MESSAGE_LIMIT = 400
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/**
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* 「交了没对」那一栏点开要看的:这个人**最近一条**提交错在哪。
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*
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* 有了它,老师看到「张三 12次」之后不用再切到提交列表、翻到这个人、点开代码 ——
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* 点一下名字就知道是编译错了还是答案错了、报的什么。err_info 是判题机塞进
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* statistic_info 的那一段,提交详情页读的也是它。
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*/
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async function lastFailureByUser(where: SQL | undefined, userIds: number[]) {
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// result 手写成 JudgeStatusValue:这条裸 SQL 读的就是 submission.result 那一列,
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// 口径要和列上的 $type 一致
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const byUser = new Map<
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number,
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{
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id: string
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problem: string
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result: JudgeStatusValue
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error: string | null
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}
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>()
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if (!userIds.length) return byUser
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// 不给 submission 起别名:where 里的条件是 drizzle 拼的,引用的是 "submission"."x"
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const rows = await db.execute<{
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user_id: number
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id: string
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problem: string
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result: JudgeStatusValue
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error: string | null
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}>(sql`
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select user_id, id, problem, result, error from (
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select
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${schema.submission.userId} as user_id,
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${schema.submission.id} as id,
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${schema.problem.displayId} as problem,
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${schema.submission.result} as result,
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left(${schema.submission.statisticInfo}->>'err_info', ${FAILURE_MESSAGE_LIMIT}) as error,
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row_number() over (
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partition by ${schema.submission.userId}
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order by ${schema.submission.createTime} desc
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) as rn
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from ${schema.submission}
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join ${schema.problem} on ${schema.problem.id} = ${schema.submission.problemId}
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where ${and(where, inArray(schema.submission.userId, userIds))}
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) t
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where rn = 1
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`)
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for (const row of rows) {
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byUser.set(row.user_id, {
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id: row.id,
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problem: row.problem,
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result: row.result,
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error: row.error,
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})
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}
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return byUser
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}
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/**
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* 「答案对了,但没按要求的语法写」的题数(AST_CHECK_FAILED)。
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*
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* 只算**最后也没改对**的:同一道题上既有 AST_CHECK_FAILED 又有 ACCEPTED,说明学生后来
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* 改成要求的写法了,不该再拿这个提醒老师。所以要先按「人 × 题」聚一层,不能直接
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* `count(distinct problem_id) filter (result = 10)`。
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*
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* 口径本身不动 —— AST_CHECK_FAILED 仍然算通过(答案确实对了,全站一致)。这里只是
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* 让教师看得见「这几个人是绕过要求做出来的」,教学上那不算达标。
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*/
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async function astOnlyByUser(where: SQL | undefined, userIds: number[]) {
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const byUser = new Map<number, number>()
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if (!userIds.length) return byUser
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const rows = await db.execute<{ user_id: number; n: number }>(sql`
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select user_id, count(*)::int as n from (
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select
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${schema.submission.userId} as user_id,
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bool_or(${schema.submission.result} = ${JudgeStatus.AST_CHECK_FAILED}) as has_ast,
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bool_or(${schema.submission.result} = ${JudgeStatus.ACCEPTED}) as has_ac
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from ${schema.submission}
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where ${and(where, inArray(schema.submission.userId, userIds))}
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group by ${schema.submission.userId}, ${schema.submission.problemId}
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) t
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where has_ast and not has_ac
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group by user_id
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`)
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for (const row of rows) byUser.set(row.user_id, row.n)
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return byUser
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}
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/**
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* 两条提交列表的用户名筛选。**两边都要匹配**:
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*
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* - `user_id in (改过名的当前用户名匹配到的账号)` —— 老师用现在的班级前缀查
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* `ks248`,要能查出这个人改名之前交的那些(生产快照:比赛提交里有 685 条
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* 挂在旧名字下);
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* - `submission.username ilike` —— 已删号的学生在 `user` 表里没有行,只剩提交里
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* 冻结的那份名字;顺带也让「按记得的旧名字查」还查得到。
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*
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* 统计接口那边只按 user_id 筛(口径是「花名册上这个班谁做完了」,已删号的人本来
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* 就不在花名册里);这两条是公开列表,不该因为改名或删号少给记录,所以取并集。
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*
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* 账号那一支**先查出 id 再拼成字面列表**,不写成 `user_id in (子查询)`:子查询夹在 OR
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* 里会被做成 hashed SubPlan,整条 OR 就不可索引,加了 trigram 索引照样全表扫。拆开之后
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* 两支各走各的索引(submission_public_metrics_idx + submission_public_username_trgm_idx),
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* 快照实测 count 65ms → 0.6ms。`ks2` 这种匹配上千个账号的宽前缀退回扫表,30~50ms,
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* 和原来持平。
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*/
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export async function usernameFilter(username: string) {
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const like = `%${username}%`
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const users = await db
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.select({ id: schema.user.id })
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.from(schema.user)
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.where(ilike(schema.user.username, like))
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const frozen = ilike(schema.submission.username, like)
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return users.length
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? or(
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inArray(
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schema.submission.userId,
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users.map((row) => row.id),
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),
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frozen,
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)!
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: frozen
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}
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|
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/**
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* 两条提交列表的题号筛选:先把题号解析成 problem.id,再按 `submission.problem_id` 筛。
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* 原来是 join problem 之后比 `lower(problem._id)`,条件落在 problem 表上,规划器只能
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* 顺着时间索引倒扫、逐行回表比对,走不上 submission_public_problem_time_idx。
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*
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* 公开列表只认公开题、比赛列表只认本场的题:题号只在这个范围内唯一(比赛题的 `_id`
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* 和公开题撞号是常态),而公开提交从不指向比赛题(快照核过,0 条)。
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* 查无此题时留恒假条件,少推一个 filter 就成了「不筛」。
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*/
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export async function problemFilter(
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displayId: string,
|
||||
contestId: number | null,
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||||
) {
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||||
const problems = await db
|
||||
.select({ id: schema.problem.id })
|
||||
.from(schema.problem)
|
||||
.where(
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and(
|
||||
sql`lower(${schema.problem.displayId}) = lower(${displayId})`,
|
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contestId === null
|
||||
? isNull(schema.problem.contestId)
|
||||
: eq(schema.problem.contestId, contestId),
|
||||
),
|
||||
)
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||||
return problems.length
|
||||
? inArray(
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||||
schema.submission.problemId,
|
||||
problems.map((row) => row.id),
|
||||
)
|
||||
: sql`false`
|
||||
}
|
||||
|
||||
/**
|
||||
* 两个统计接口共用的范围:时间窗 + 题号。**用户名不在里面** —— 统计那边是
|
||||
* ilike 模糊匹配(填 ks251 要匹配整个班),明细那边必须精确到人,口径不同。
|
||||
* 两边都是先拿用户名去 `user` 表解析成 user_id,再按 user_id 筛提交。
|
||||
*/
|
||||
type StatisticsScope =
|
||||
| { ok: true; filters: SQL[]; problemCount: number }
|
||||
| { ok: false; status: 400 | 404; code: string; message: string }
|
||||
|
||||
async function statisticsScope(c: {
|
||||
req: { query(name: string): string | undefined }
|
||||
}): Promise<StatisticsScope> {
|
||||
const range = statisticsRange(c)
|
||||
if (!range) {
|
||||
return {
|
||||
ok: false,
|
||||
status: 400,
|
||||
code: "invalid-request",
|
||||
message: "end is required",
|
||||
}
|
||||
}
|
||||
|
||||
const filters = [
|
||||
isNull(schema.submission.contestId),
|
||||
sql`${schema.submission.createTime} <= ${range.end}`,
|
||||
]
|
||||
if (range.start)
|
||||
filters.push(sql`${schema.submission.createTime} >= ${range.start}`)
|
||||
|
||||
const displayIds = parseDisplayIds(c.req.query("problemId") ?? "")
|
||||
if (displayIds.length > STATISTICS_MAX_PROBLEMS) {
|
||||
return {
|
||||
ok: false,
|
||||
status: 400,
|
||||
code: "invalid-request",
|
||||
message: `At most ${STATISTICS_MAX_PROBLEMS} problems`,
|
||||
}
|
||||
}
|
||||
if (displayIds.length) {
|
||||
const { ids, missing } = await findPublicProblemsByDisplayIds(displayIds)
|
||||
if (missing) {
|
||||
return {
|
||||
ok: false,
|
||||
status: 404,
|
||||
code: "problem-not-found",
|
||||
message: `Problem ${missing} does not exist`,
|
||||
}
|
||||
}
|
||||
filters.push(inArray(schema.submission.problemId, ids))
|
||||
}
|
||||
|
||||
return { ok: true, filters, problemCount: displayIds.length }
|
||||
}
|
||||
|
||||
submissionStatisticsRoutes.get(
|
||||
"/submissions/statistics",
|
||||
requireTeacher,
|
||||
async (c) => {
|
||||
const scope = await statisticsScope(c)
|
||||
if (!scope.ok) return failure(c, scope.status, scope.code, scope.message)
|
||||
const filters = scope.filters
|
||||
|
||||
const username = c.req.query("username")?.trim()
|
||||
// 用户名先解析成账号,再拿 user_id 去筛提交。这一趟查询挡在 Promise.all 前面,
|
||||
// 但换掉的是下面**四条**语句各一次的 submission 全表扫:`ilike` 走不了索引,
|
||||
// 换成 `user_id in (...)` 之后四条全走索引(生产快照实测单条 18448 → 537
|
||||
// buffers;同一个快照上整个接口查一个班 120~250ms → 10ms 上下),多这一次往返是赚的。
|
||||
const matched = username ? await matchedUsers(username) : []
|
||||
if (username) {
|
||||
const matchedIds = matched.map((row) => row.id)
|
||||
// 一个账号都没匹配上时得留个恒假条件。少推一个 filter 的话过滤条件整个消失,
|
||||
// 「查无此班」会变成「全站统计」
|
||||
filters.push(
|
||||
matchedIds.length
|
||||
? inArray(schema.submission.userId, matchedIds)
|
||||
: sql`false`,
|
||||
)
|
||||
}
|
||||
const where = and(...filters)
|
||||
// 花名册:只有未禁用的普通用户算进班级人数和「谁没做」,教师和管理员不进分母
|
||||
const rosterRows = matched.filter(
|
||||
(row) => !row.isDisabled && row.adminType === "Regular User",
|
||||
)
|
||||
|
||||
const acceptedFilter = sql`count(*) filter (where ${inArray(schema.submission.result, ACCEPTED_RESULTS)})`
|
||||
// 判题中的条数。要单独数出来,正确率的分母才能把它们摘掉
|
||||
const judgingFilter = sql`count(*) filter (where ${inArray(schema.submission.result, UNJUDGED_RESULTS)})`
|
||||
/**
|
||||
* **解决的题数**,不是通过的提交条数。同一道题重复 AC(改完再交一次仍然对)
|
||||
* 在这里只算一道 —— 表格那一列叫「已解决」,数条数就名不副实了。
|
||||
* 指定了题号时它最多是 1,不指定时才看得出差别(老师查「这节课全班」就是这种)。
|
||||
*/
|
||||
const solvedFilter = sql`count(distinct ${schema.submission.problemId}) filter (where ${inArray(schema.submission.result, ACCEPTED_RESULTS)})`
|
||||
|
||||
const [[totals], perUser] = await Promise.all([
|
||||
db
|
||||
.select({
|
||||
total: count(),
|
||||
accepted: acceptedFilter.mapWith(Number),
|
||||
judging: judgingFilter.mapWith(Number),
|
||||
})
|
||||
.from(schema.submission)
|
||||
.where(where),
|
||||
db
|
||||
.select({
|
||||
userId: schema.submission.userId,
|
||||
/**
|
||||
* 显示的是**当前**用户名,从 user 表 join 出来 —— 按 submission.username
|
||||
* 分组的话,改过名的学生会裂成新旧两行,两边各算各的,谁都够不到「全做完」。
|
||||
*
|
||||
* 已删号的学生 user 表里没有行,退回提交里冻结的那份名字(下面的
|
||||
* personCount 兜底就是给这种情况的)。
|
||||
*/
|
||||
username: sql<string>`coalesce(${schema.user.username}, max(${schema.submission.username}))`,
|
||||
className: schema.user.className,
|
||||
// 不传用户名时「交了没全对」那一栏靠它把教师和禁用账号挡在外面 ——
|
||||
// 传了用户名时这件事是花名册(rosterRows)做的
|
||||
isDisabled: schema.user.isDisabled,
|
||||
adminType: schema.user.adminType,
|
||||
submissionCount: count(),
|
||||
acceptedCount: acceptedFilter.mapWith(Number),
|
||||
solvedCount: solvedFilter.mapWith(Number),
|
||||
judgingCount: judgingFilter.mapWith(Number),
|
||||
})
|
||||
.from(schema.submission)
|
||||
.leftJoin(schema.user, eq(schema.user.id, schema.submission.userId))
|
||||
.where(where)
|
||||
// user_id 定了 user 那一行就定了,把 username / class_name 一起放进 group by
|
||||
// 不会多分出组来,但省掉再对它们套一层聚合函数
|
||||
.groupBy(
|
||||
schema.submission.userId,
|
||||
schema.user.username,
|
||||
schema.user.className,
|
||||
schema.user.isDisabled,
|
||||
schema.user.adminType,
|
||||
)
|
||||
.orderBy(desc(count())),
|
||||
])
|
||||
|
||||
const submissionCount = totals?.total ?? 0
|
||||
const acceptedCount = totals?.accepted ?? 0
|
||||
const judgingCount = totals?.judging ?? 0
|
||||
// 正确率的分母是**判完的条数**,不是总条数
|
||||
const judgedCount = submissionCount - judgingCount
|
||||
|
||||
/**
|
||||
* 「做完了」的判定。**指定了几道题,就要几道都解决**(这是教师选的口径:
|
||||
* 「今天布置三道,谁全做完了」)—— 做出两道差一道的人落在「交了没全对」那一栏,
|
||||
* 那里带着 `solvedCount`,老师看得出他差几道。
|
||||
*
|
||||
* 只填一道题时 `solvedCount >= 1` 和原来的 `acceptedCount > 0` 完全等价;
|
||||
* 不填题号时无所谓「全部」,退回「至少做出一道」。
|
||||
*/
|
||||
const requiredSolved = scope.problemCount
|
||||
const isDone = (row: { solvedCount: number; acceptedCount: number }) =>
|
||||
requiredSolved > 0
|
||||
? row.solvedCount >= requiredSolved
|
||||
: row.acceptedCount > 0
|
||||
|
||||
/**
|
||||
* 「提交记录」那张表列的是**窗口里交过东西的所有人**,`done` 标出谁做完了 ——
|
||||
* 原来只给做完的人,于是一次没对的学生连同他的提交在这张表里根本不存在,
|
||||
* 教师想看「他到底错在哪」得切到提交列表再翻。展开一行拉的是那个人的全部
|
||||
* 提交(GET /submissions/statistics/items 不按结果过滤),对错都在里面。
|
||||
*
|
||||
* 「完成人数」这些数字跟着 `done` 算,不是 `data.length`。
|
||||
*/
|
||||
const doneCount = perUser.filter(isDone).length
|
||||
// 要等 perUser 回来才能查,所以进不了上面那个 Promise.all
|
||||
const astOnlyByUserMap = await astOnlyByUser(
|
||||
where,
|
||||
perUser.map((row) => row.userId),
|
||||
)
|
||||
|
||||
const submittedUserIds = new Set(perUser.map((row) => row.userId))
|
||||
|
||||
const data = perUser.map((row) => ({
|
||||
username: row.username,
|
||||
className: row.className,
|
||||
submissionCount: row.submissionCount,
|
||||
acceptedCount: row.acceptedCount,
|
||||
solvedCount: row.solvedCount,
|
||||
astOnlyCount: astOnlyByUserMap.get(row.userId) ?? 0,
|
||||
judgingCount: row.judgingCount,
|
||||
correctRate: judgedRate(
|
||||
row.acceptedCount,
|
||||
row.submissionCount - row.judgingCount,
|
||||
),
|
||||
done: isDone(row),
|
||||
}))
|
||||
|
||||
const dataUnaccepted = rosterRows
|
||||
.filter((row) => !submittedUserIds.has(row.id))
|
||||
.map((row) => ({
|
||||
username: row.username,
|
||||
realName: stripClassPrefix(row.username, row.className),
|
||||
}))
|
||||
|
||||
/**
|
||||
* 交了但没做完的:包括一道都没对的,也包括三道里做出两道的。
|
||||
*
|
||||
* **传了用户名时按花名册取**,和 dataUnaccepted 同一个范围,查一个班不会冒出
|
||||
* 一堆别的班的人。
|
||||
*
|
||||
* 不传用户名时没有花名册,这一栏原先跟着空掉 —— 于是只交了错误答案的学生
|
||||
* 「已完成」那张表进不去(没做完)、「未完成」那一栏也没有,整个人从屏幕上
|
||||
* 消失,看起来就像统计只认成功的提交。这种情况退回「有提交但没做完的全部人」,
|
||||
* 教师和禁用账号照样排除(否则老师自己试题留下的错误提交会混进点名名单)。
|
||||
*
|
||||
* 「还没交」那一栏没有花名册是真的算不出来(不知道该有谁),仍然为空。
|
||||
*/
|
||||
const rosterIds = new Set(rosterRows.map((row) => row.id))
|
||||
const attemptedRows = perUser.filter((row) => {
|
||||
if (isDone(row)) return false
|
||||
return username
|
||||
? rosterIds.has(row.userId)
|
||||
: !row.isDisabled && row.adminType === "Regular User"
|
||||
})
|
||||
const failureByUser = await lastFailureByUser(
|
||||
where,
|
||||
attemptedRows.map((row) => row.userId),
|
||||
)
|
||||
const dataAttempted = attemptedRows.map((row) => ({
|
||||
username: row.username,
|
||||
/**
|
||||
* 剥前缀只在**查了某个班**的时候做:那时满屏都是同一个班,留着 `ks251` 是噪音。
|
||||
* 不传用户名的全站视图里各班混在一起,剥完只剩一串重名的名字,反而认不出谁,
|
||||
* 所以原样给完整用户名。班名取 perUser join 出来的那一列,和花名册同一份数据。
|
||||
*/
|
||||
realName: username
|
||||
? stripClassPrefix(row.username, row.className)
|
||||
: row.username,
|
||||
submissionCount: row.submissionCount,
|
||||
solvedCount: row.solvedCount,
|
||||
lastFailure: failureByUser.get(row.userId) ?? null,
|
||||
}))
|
||||
|
||||
// 「学生已删号但提交记录还在」时完成人数会大于花名册人数,分母兜到完成人数为止。
|
||||
// 旧后端在这之前还先算了一个 person_rate 一起下发,前端从来没读过它(完成度是
|
||||
// 前端自己按「减掉请假人数之后的分母」重算的),所以这条链路上只留 person_count。
|
||||
let personCount = rosterRows.length
|
||||
if (personCount && personCount < doneCount) personCount = doneCount
|
||||
|
||||
return success(c, {
|
||||
submissionCount,
|
||||
acceptedCount,
|
||||
judgingCount,
|
||||
correctRate: judgedRate(acceptedCount, judgedCount),
|
||||
personCount,
|
||||
data,
|
||||
dataUnaccepted,
|
||||
dataAttempted,
|
||||
} satisfies SubmissionStatistics)
|
||||
},
|
||||
)
|
||||
|
||||
/**
|
||||
* 统计面板展开一行时拉这个人的提交明细。
|
||||
*
|
||||
* 用户名这里是**精确匹配**,不是统计接口那种 ilike —— 那边填 `ks251` 要圈出整个班,
|
||||
* 这边是「点开的这一行是谁」。时间窗和题号沿用同一个 scope,不然展开行看到的
|
||||
* 会是另一个范围的数据。
|
||||
*/
|
||||
submissionStatisticsRoutes.get(
|
||||
"/submissions/statistics/items",
|
||||
requireTeacher,
|
||||
async (c) => {
|
||||
const username = c.req.query("username")?.trim()
|
||||
if (!username)
|
||||
return failure(c, 400, "invalid-request", "username is required")
|
||||
|
||||
const scope = await statisticsScope(c)
|
||||
if (!scope.ok) return failure(c, scope.status, scope.code, scope.message)
|
||||
|
||||
/**
|
||||
* 展开的那一行给的是**当前**用户名,先换成 user_id 再查 —— 直接按
|
||||
* `submission.username` 精确匹配的话,改过名的学生展开来是空的(他的提交
|
||||
* 全挂在旧名字下)。
|
||||
*
|
||||
* 查不到账号才退回按提交里冻结的用户名匹配:已删号的学生仍然会出现在统计
|
||||
* 表格里(那一行的名字取自提交),展开行不能因此空着。
|
||||
*/
|
||||
const [account] = await db
|
||||
.select({ id: schema.user.id })
|
||||
.from(schema.user)
|
||||
.where(eq(schema.user.username, username))
|
||||
.limit(1)
|
||||
const identity = account
|
||||
? eq(schema.submission.userId, account.id)
|
||||
: eq(schema.submission.username, username)
|
||||
|
||||
// 多取一条,好知道是不是被截断了
|
||||
// innerJoin 不会漏行:submission.problem_id 是 NOT NULL 且外键是 NO ACTION,
|
||||
// 题目删不掉(真要删会被外键拦住并提示改为隐藏)
|
||||
const rows = await db
|
||||
.select({
|
||||
id: schema.submission.id,
|
||||
result: schema.submission.result,
|
||||
createTime: schema.submission.createTime,
|
||||
problem: schema.problem.displayId,
|
||||
problemTitle: schema.problem.title,
|
||||
})
|
||||
.from(schema.submission)
|
||||
.innerJoin(
|
||||
schema.problem,
|
||||
eq(schema.problem.id, schema.submission.problemId),
|
||||
)
|
||||
.where(and(...scope.filters, identity))
|
||||
.orderBy(desc(schema.submission.createTime), desc(schema.submission.id))
|
||||
.limit(STATISTICS_ITEMS_LIMIT + 1)
|
||||
|
||||
const truncated = rows.length > STATISTICS_ITEMS_LIMIT
|
||||
return success(c, {
|
||||
items: rows.slice(0, STATISTICS_ITEMS_LIMIT),
|
||||
truncated,
|
||||
} satisfies SubmissionStatisticsItems)
|
||||
},
|
||||
)
|
||||
@@ -8,9 +8,6 @@ import {
|
||||
type SubmissionDetail,
|
||||
type SubmissionList,
|
||||
type SubmissionListItem,
|
||||
type SubmissionStatistics,
|
||||
type SubmissionStatisticsItems,
|
||||
type TodaySubmissionStatistics,
|
||||
} from "@oj2/contract"
|
||||
import {
|
||||
and,
|
||||
@@ -18,7 +15,6 @@ import {
|
||||
desc,
|
||||
eq,
|
||||
gt,
|
||||
ilike,
|
||||
inArray,
|
||||
isNull,
|
||||
or,
|
||||
@@ -31,37 +27,29 @@ import {
|
||||
optionalAuth,
|
||||
requireAuth,
|
||||
requireSuperAdmin,
|
||||
requireTeacher,
|
||||
} from "../auth/middleware"
|
||||
import type { AuthUser } from "../auth/session"
|
||||
import { db, schema } from "../db"
|
||||
import { failure, success } from "../http"
|
||||
import {
|
||||
JudgeStatus,
|
||||
UNJUDGED_RESULTS,
|
||||
type JudgeStatusValue,
|
||||
} from "../judge/status"
|
||||
import { JudgeStatus } from "../judge/status"
|
||||
import { judgeQueue } from "../queue"
|
||||
import {
|
||||
canAccessContest,
|
||||
contestStatus,
|
||||
findAccessibleContest,
|
||||
isContestAdmin,
|
||||
requireContestAccess,
|
||||
type ContestEnv,
|
||||
} from "../services/contest"
|
||||
import { CodeFormatError, formatCode } from "../services/format-code"
|
||||
import { getBooleanOption } from "../services/options"
|
||||
import { consumeToken } from "../services/throttling"
|
||||
import { localTime, todayStart } from "../time"
|
||||
import { todayStart } from "../time"
|
||||
import { asFilterValue, isAdminRole, queryInteger } from "./helpers"
|
||||
import {
|
||||
asFilterValue,
|
||||
isAdminRole,
|
||||
matchedUsers,
|
||||
queryInteger,
|
||||
rounded,
|
||||
stripClassPrefix,
|
||||
} from "./helpers"
|
||||
problemFilter,
|
||||
submissionStatisticsRoutes,
|
||||
usernameFilter,
|
||||
} from "./submission-statistics"
|
||||
|
||||
export const submissionRoutes = new Hono<ContestEnv>()
|
||||
|
||||
@@ -219,660 +207,7 @@ submissionRoutes.get("/submissions/today-count", async (c) => {
|
||||
return success(c, row?.value ?? 0)
|
||||
})
|
||||
|
||||
const ACCEPTED_RESULTS = [JudgeStatus.ACCEPTED, JudgeStatus.AST_CHECK_FAILED]
|
||||
|
||||
/** 正确率。分母是判完的条数,一条都还没判完时给 0 而不是 NaN */
|
||||
function judgedRate(accepted: number, judged: number) {
|
||||
return judged > 0 ? rounded((accepted / judged) * 100) : 0
|
||||
}
|
||||
|
||||
/**
|
||||
* 「今日提交数」标签点开的统计。**公开、只出聚合数**(没有用户名、没有代码,
|
||||
* 热门题只算公开可见的题),口径和那颗标签一致:东八区今天 + 非比赛提交。
|
||||
*
|
||||
* 按钟点切用 `localTime()`,不能写 `extract(hour from create_time)` ——
|
||||
* 后者按数据库会话时区算,容器是 UTC,整张分布图会整体左移 8 小时。
|
||||
*/
|
||||
submissionRoutes.get(
|
||||
"/submissions/today-statistics",
|
||||
optionalAuth,
|
||||
async (c) => {
|
||||
/**
|
||||
* 「提交列表对学生全开」关掉时(考试那种场合)不给热门题这张表 —— 总数、正确率
|
||||
* 这些聚合数原本就从公开的 today-count 看得出来,但「哪几道题在被刷」已经贴近
|
||||
* 提交列表本身的内容了,得跟着同一个开关走。数字照给,不然标签说 21、弹框说 0。
|
||||
*/
|
||||
const showProblems =
|
||||
(await getBooleanOption("submission_list_show_all", true)) ||
|
||||
isAdminRole(c.get("user"))
|
||||
const where = and(
|
||||
isNull(schema.submission.contestId),
|
||||
sql`${schema.submission.createTime} >= ${todayStart()}`,
|
||||
)
|
||||
const acceptedFilter = sql`count(*) filter (where ${inArray(schema.submission.result, ACCEPTED_RESULTS)})`
|
||||
const judgingFilter = sql`count(*) filter (where ${inArray(schema.submission.result, UNJUDGED_RESULTS)})`
|
||||
const hour = sql<number>`extract(hour from ${localTime(schema.submission.createTime)})::int`
|
||||
|
||||
const [[totals], hourRows, languageRows, resultRows, problemRows] =
|
||||
await Promise.all([
|
||||
db
|
||||
.select({
|
||||
total: count(),
|
||||
accepted: acceptedFilter.mapWith(Number),
|
||||
judging: judgingFilter.mapWith(Number),
|
||||
userCount:
|
||||
sql<number>`count(distinct ${schema.submission.userId})`.mapWith(
|
||||
Number,
|
||||
),
|
||||
})
|
||||
.from(schema.submission)
|
||||
.where(where),
|
||||
db
|
||||
.select({ hour, value: count() })
|
||||
.from(schema.submission)
|
||||
.where(where)
|
||||
.groupBy(hour),
|
||||
db
|
||||
.select({ language: schema.submission.language, value: count() })
|
||||
.from(schema.submission)
|
||||
.where(where)
|
||||
.groupBy(schema.submission.language)
|
||||
.orderBy(desc(count())),
|
||||
db
|
||||
.select({ result: schema.submission.result, value: count() })
|
||||
.from(schema.submission)
|
||||
.where(where)
|
||||
.groupBy(schema.submission.result)
|
||||
.orderBy(desc(count())),
|
||||
showProblems
|
||||
? db
|
||||
.select({
|
||||
displayId: schema.problem.displayId,
|
||||
title: schema.problem.title,
|
||||
value: count(),
|
||||
accepted: acceptedFilter.mapWith(Number),
|
||||
})
|
||||
.from(schema.submission)
|
||||
.innerJoin(
|
||||
schema.problem,
|
||||
eq(schema.problem.id, schema.submission.problemId),
|
||||
)
|
||||
// 隐藏题目不出现在这张表里:接口不需要登录,标题本身就是不该外露的东西
|
||||
.where(and(where, eq(schema.problem.visible, true)))
|
||||
.groupBy(
|
||||
schema.problem.id,
|
||||
schema.problem.displayId,
|
||||
schema.problem.title,
|
||||
)
|
||||
.orderBy(desc(count()))
|
||||
.limit(10)
|
||||
: [],
|
||||
])
|
||||
|
||||
const total = totals?.total ?? 0
|
||||
const judging = totals?.judging ?? 0
|
||||
const hours = Array.from({ length: 24 }, () => 0)
|
||||
for (const row of hourRows) hours[row.hour] = row.value
|
||||
|
||||
return success(c, {
|
||||
total,
|
||||
accepted: totals?.accepted ?? 0,
|
||||
judging,
|
||||
correctRate: judgedRate(totals?.accepted ?? 0, total - judging),
|
||||
userCount: totals?.userCount ?? 0,
|
||||
hours,
|
||||
languages: languageRows.map((row) => ({
|
||||
language: row.language,
|
||||
count: row.value,
|
||||
})),
|
||||
results: resultRows.map((row) => ({
|
||||
result: row.result,
|
||||
count: row.value,
|
||||
})),
|
||||
problems: problemRows.map((row) => ({
|
||||
problem: row.displayId,
|
||||
problemTitle: row.title,
|
||||
count: row.value,
|
||||
acceptedCount: row.accepted,
|
||||
})),
|
||||
} satisfies TodaySubmissionStatistics)
|
||||
},
|
||||
)
|
||||
|
||||
/**
|
||||
* 统计接口共用的时间窗解析。旧后端 `end` 必填、`start` 可选(不给就是「全部时段」)。
|
||||
*/
|
||||
function statisticsRange(c: {
|
||||
req: { query(name: string): string | undefined }
|
||||
}) {
|
||||
const end = c.req.query("end")?.trim()
|
||||
if (!end) return null
|
||||
const start = c.req.query("start")?.trim()
|
||||
return { start: start || null, end }
|
||||
}
|
||||
|
||||
/** 一次最多查几道题。课堂上一节课布置三五道,20 是留足了余量的上限 */
|
||||
const STATISTICS_MAX_PROBLEMS = 20
|
||||
|
||||
/**
|
||||
* 题号框允许一次填几道:`1001,1005,1010`。中英文逗号、空格、分号都当分隔符 ——
|
||||
* 老师在投影前手敲,不该因为打了个全角逗号就查不出来。
|
||||
*/
|
||||
function parseDisplayIds(raw: string) {
|
||||
const seen = new Set<string>()
|
||||
const ids: string[] = []
|
||||
for (const part of raw.split(/[,,;;\s]+/)) {
|
||||
const id = part.trim()
|
||||
if (!id) continue
|
||||
const key = id.toLowerCase()
|
||||
if (seen.has(key)) continue
|
||||
seen.add(key)
|
||||
ids.push(id)
|
||||
}
|
||||
return ids
|
||||
}
|
||||
|
||||
/**
|
||||
* 按题号(展示用的 _id)定位公开题目。**有一个找不到就整体报错**,不退化成「全部题目」——
|
||||
* 否则教师打错一个字就会看到全站数据还以为是这几道题的。
|
||||
*/
|
||||
async function findPublicProblemsByDisplayIds(displayIds: string[]) {
|
||||
const lowered = displayIds.map((id) => id.toLowerCase())
|
||||
const rows = await db
|
||||
.select({ id: schema.problem.id, displayId: schema.problem.displayId })
|
||||
.from(schema.problem)
|
||||
.where(
|
||||
and(
|
||||
inArray(sql`lower(${schema.problem.displayId})`, lowered),
|
||||
isNull(schema.problem.contestId),
|
||||
eq(schema.problem.visible, true),
|
||||
),
|
||||
)
|
||||
const found = new Set(rows.map((row) => row.displayId.toLowerCase()))
|
||||
const missing = displayIds.find((id) => !found.has(id.toLowerCase()))
|
||||
return { ids: rows.map((row) => row.id), missing: missing ?? null }
|
||||
}
|
||||
|
||||
/**
|
||||
* 展开行一次只看一个人(表格的 updateExpandedRowKeys 只留最后一个 key),所以明细
|
||||
* **按需拉**,不再随统计一起下发。
|
||||
*
|
||||
* 原来是随 data 一起给所有人各带一份:生产快照实测,「全部时段 + 不填条件」要搬
|
||||
* 49108 行(最早那版不截断是 105631 行),而其中真正被人看到的最多一个人的那几十条。
|
||||
*/
|
||||
const STATISTICS_ITEMS_LIMIT = 200
|
||||
|
||||
/** 错误摘要截断长度。编译错误能刷几十行,弹层里放不下,也没必要 */
|
||||
const FAILURE_MESSAGE_LIMIT = 400
|
||||
|
||||
/**
|
||||
* 「交了没对」那一栏点开要看的:这个人**最近一条**提交错在哪。
|
||||
*
|
||||
* 有了它,老师看到「张三 12次」之后不用再切到提交列表、翻到这个人、点开代码 ——
|
||||
* 点一下名字就知道是编译错了还是答案错了、报的什么。err_info 是判题机塞进
|
||||
* statistic_info 的那一段,提交详情页读的也是它。
|
||||
*/
|
||||
async function lastFailureByUser(where: SQL | undefined, userIds: number[]) {
|
||||
// result 手写成 JudgeStatusValue:这条裸 SQL 读的就是 submission.result 那一列,
|
||||
// 口径要和列上的 $type 一致
|
||||
const byUser = new Map<
|
||||
number,
|
||||
{
|
||||
id: string
|
||||
problem: string
|
||||
result: JudgeStatusValue
|
||||
error: string | null
|
||||
}
|
||||
>()
|
||||
if (!userIds.length) return byUser
|
||||
|
||||
// 不给 submission 起别名:where 里的条件是 drizzle 拼的,引用的是 "submission"."x"
|
||||
const rows = await db.execute<{
|
||||
user_id: number
|
||||
id: string
|
||||
problem: string
|
||||
result: JudgeStatusValue
|
||||
error: string | null
|
||||
}>(sql`
|
||||
select user_id, id, problem, result, error from (
|
||||
select
|
||||
${schema.submission.userId} as user_id,
|
||||
${schema.submission.id} as id,
|
||||
${schema.problem.displayId} as problem,
|
||||
${schema.submission.result} as result,
|
||||
left(${schema.submission.statisticInfo}->>'err_info', ${FAILURE_MESSAGE_LIMIT}) as error,
|
||||
row_number() over (
|
||||
partition by ${schema.submission.userId}
|
||||
order by ${schema.submission.createTime} desc
|
||||
) as rn
|
||||
from ${schema.submission}
|
||||
join ${schema.problem} on ${schema.problem.id} = ${schema.submission.problemId}
|
||||
where ${and(where, inArray(schema.submission.userId, userIds))}
|
||||
) t
|
||||
where rn = 1
|
||||
`)
|
||||
|
||||
for (const row of rows) {
|
||||
byUser.set(row.user_id, {
|
||||
id: row.id,
|
||||
problem: row.problem,
|
||||
result: row.result,
|
||||
error: row.error,
|
||||
})
|
||||
}
|
||||
return byUser
|
||||
}
|
||||
|
||||
/**
|
||||
* 「答案对了,但没按要求的语法写」的题数(AST_CHECK_FAILED)。
|
||||
*
|
||||
* 只算**最后也没改对**的:同一道题上既有 AST_CHECK_FAILED 又有 ACCEPTED,说明学生后来
|
||||
* 改成要求的写法了,不该再拿这个提醒老师。所以要先按「人 × 题」聚一层,不能直接
|
||||
* `count(distinct problem_id) filter (result = 10)`。
|
||||
*
|
||||
* 口径本身不动 —— AST_CHECK_FAILED 仍然算通过(答案确实对了,全站一致)。这里只是
|
||||
* 让教师看得见「这几个人是绕过要求做出来的」,教学上那不算达标。
|
||||
*/
|
||||
async function astOnlyByUser(where: SQL | undefined, userIds: number[]) {
|
||||
const byUser = new Map<number, number>()
|
||||
if (!userIds.length) return byUser
|
||||
|
||||
const rows = await db.execute<{ user_id: number; n: number }>(sql`
|
||||
select user_id, count(*)::int as n from (
|
||||
select
|
||||
${schema.submission.userId} as user_id,
|
||||
bool_or(${schema.submission.result} = ${JudgeStatus.AST_CHECK_FAILED}) as has_ast,
|
||||
bool_or(${schema.submission.result} = ${JudgeStatus.ACCEPTED}) as has_ac
|
||||
from ${schema.submission}
|
||||
where ${and(where, inArray(schema.submission.userId, userIds))}
|
||||
group by ${schema.submission.userId}, ${schema.submission.problemId}
|
||||
) t
|
||||
where has_ast and not has_ac
|
||||
group by user_id
|
||||
`)
|
||||
for (const row of rows) byUser.set(row.user_id, row.n)
|
||||
return byUser
|
||||
}
|
||||
|
||||
/**
|
||||
* 两条提交列表的用户名筛选。**两边都要匹配**:
|
||||
*
|
||||
* - `user_id in (改过名的当前用户名匹配到的账号)` —— 老师用现在的班级前缀查
|
||||
* `ks248`,要能查出这个人改名之前交的那些(生产快照:比赛提交里有 685 条
|
||||
* 挂在旧名字下);
|
||||
* - `submission.username ilike` —— 已删号的学生在 `user` 表里没有行,只剩提交里
|
||||
* 冻结的那份名字;顺带也让「按记得的旧名字查」还查得到。
|
||||
*
|
||||
* 统计接口那边只按 user_id 筛(口径是「花名册上这个班谁做完了」,已删号的人本来
|
||||
* 就不在花名册里);这两条是公开列表,不该因为改名或删号少给记录,所以取并集。
|
||||
*
|
||||
* 账号那一支**先查出 id 再拼成字面列表**,不写成 `user_id in (子查询)`:子查询夹在 OR
|
||||
* 里会被做成 hashed SubPlan,整条 OR 就不可索引,加了 trigram 索引照样全表扫。拆开之后
|
||||
* 两支各走各的索引(submission_public_metrics_idx + submission_public_username_trgm_idx),
|
||||
* 快照实测 count 65ms → 0.6ms。`ks2` 这种匹配上千个账号的宽前缀退回扫表,30~50ms,
|
||||
* 和原来持平。
|
||||
*/
|
||||
async function usernameFilter(username: string) {
|
||||
const like = `%${username}%`
|
||||
const users = await db
|
||||
.select({ id: schema.user.id })
|
||||
.from(schema.user)
|
||||
.where(ilike(schema.user.username, like))
|
||||
const frozen = ilike(schema.submission.username, like)
|
||||
return users.length
|
||||
? or(
|
||||
inArray(
|
||||
schema.submission.userId,
|
||||
users.map((row) => row.id),
|
||||
),
|
||||
frozen,
|
||||
)!
|
||||
: frozen
|
||||
}
|
||||
|
||||
/**
|
||||
* 两条提交列表的题号筛选:先把题号解析成 problem.id,再按 `submission.problem_id` 筛。
|
||||
* 原来是 join problem 之后比 `lower(problem._id)`,条件落在 problem 表上,规划器只能
|
||||
* 顺着时间索引倒扫、逐行回表比对,走不上 submission_public_problem_time_idx。
|
||||
*
|
||||
* 公开列表只认公开题、比赛列表只认本场的题:题号只在这个范围内唯一(比赛题的 `_id`
|
||||
* 和公开题撞号是常态),而公开提交从不指向比赛题(快照核过,0 条)。
|
||||
* 查无此题时留恒假条件,少推一个 filter 就成了「不筛」。
|
||||
*/
|
||||
async function problemFilter(displayId: string, contestId: number | null) {
|
||||
const problems = await db
|
||||
.select({ id: schema.problem.id })
|
||||
.from(schema.problem)
|
||||
.where(
|
||||
and(
|
||||
sql`lower(${schema.problem.displayId}) = lower(${displayId})`,
|
||||
contestId === null
|
||||
? isNull(schema.problem.contestId)
|
||||
: eq(schema.problem.contestId, contestId),
|
||||
),
|
||||
)
|
||||
return problems.length
|
||||
? inArray(
|
||||
schema.submission.problemId,
|
||||
problems.map((row) => row.id),
|
||||
)
|
||||
: sql`false`
|
||||
}
|
||||
|
||||
/**
|
||||
* 两个统计接口共用的范围:时间窗 + 题号。**用户名不在里面** —— 统计那边是
|
||||
* ilike 模糊匹配(填 ks251 要匹配整个班),明细那边必须精确到人,口径不同。
|
||||
* 两边都是先拿用户名去 `user` 表解析成 user_id,再按 user_id 筛提交。
|
||||
*/
|
||||
type StatisticsScope =
|
||||
| { ok: true; filters: SQL[]; problemCount: number }
|
||||
| { ok: false; status: 400 | 404; code: string; message: string }
|
||||
|
||||
async function statisticsScope(c: {
|
||||
req: { query(name: string): string | undefined }
|
||||
}): Promise<StatisticsScope> {
|
||||
const range = statisticsRange(c)
|
||||
if (!range) {
|
||||
return {
|
||||
ok: false,
|
||||
status: 400,
|
||||
code: "invalid-request",
|
||||
message: "end is required",
|
||||
}
|
||||
}
|
||||
|
||||
const filters = [
|
||||
isNull(schema.submission.contestId),
|
||||
sql`${schema.submission.createTime} <= ${range.end}`,
|
||||
]
|
||||
if (range.start)
|
||||
filters.push(sql`${schema.submission.createTime} >= ${range.start}`)
|
||||
|
||||
const displayIds = parseDisplayIds(c.req.query("problemId") ?? "")
|
||||
if (displayIds.length > STATISTICS_MAX_PROBLEMS) {
|
||||
return {
|
||||
ok: false,
|
||||
status: 400,
|
||||
code: "invalid-request",
|
||||
message: `At most ${STATISTICS_MAX_PROBLEMS} problems`,
|
||||
}
|
||||
}
|
||||
if (displayIds.length) {
|
||||
const { ids, missing } = await findPublicProblemsByDisplayIds(displayIds)
|
||||
if (missing) {
|
||||
return {
|
||||
ok: false,
|
||||
status: 404,
|
||||
code: "problem-not-found",
|
||||
message: `Problem ${missing} does not exist`,
|
||||
}
|
||||
}
|
||||
filters.push(inArray(schema.submission.problemId, ids))
|
||||
}
|
||||
|
||||
return { ok: true, filters, problemCount: displayIds.length }
|
||||
}
|
||||
|
||||
submissionRoutes.get("/submissions/statistics", requireTeacher, async (c) => {
|
||||
const scope = await statisticsScope(c)
|
||||
if (!scope.ok) return failure(c, scope.status, scope.code, scope.message)
|
||||
const filters = scope.filters
|
||||
|
||||
const username = c.req.query("username")?.trim()
|
||||
// 用户名先解析成账号,再拿 user_id 去筛提交。这一趟查询挡在 Promise.all 前面,
|
||||
// 但换掉的是下面**四条**语句各一次的 submission 全表扫:`ilike` 走不了索引,
|
||||
// 换成 `user_id in (...)` 之后四条全走索引(生产快照实测单条 18448 → 537
|
||||
// buffers;同一个快照上整个接口查一个班 120~250ms → 10ms 上下),多这一次往返是赚的。
|
||||
const matched = username ? await matchedUsers(username) : []
|
||||
if (username) {
|
||||
const matchedIds = matched.map((row) => row.id)
|
||||
// 一个账号都没匹配上时得留个恒假条件。少推一个 filter 的话过滤条件整个消失,
|
||||
// 「查无此班」会变成「全站统计」
|
||||
filters.push(
|
||||
matchedIds.length
|
||||
? inArray(schema.submission.userId, matchedIds)
|
||||
: sql`false`,
|
||||
)
|
||||
}
|
||||
const where = and(...filters)
|
||||
// 花名册:只有未禁用的普通用户算进班级人数和「谁没做」,教师和管理员不进分母
|
||||
const rosterRows = matched.filter(
|
||||
(row) => !row.isDisabled && row.adminType === "Regular User",
|
||||
)
|
||||
|
||||
const acceptedFilter = sql`count(*) filter (where ${inArray(schema.submission.result, ACCEPTED_RESULTS)})`
|
||||
// 判题中的条数。要单独数出来,正确率的分母才能把它们摘掉
|
||||
const judgingFilter = sql`count(*) filter (where ${inArray(schema.submission.result, UNJUDGED_RESULTS)})`
|
||||
/**
|
||||
* **解决的题数**,不是通过的提交条数。同一道题重复 AC(改完再交一次仍然对)
|
||||
* 在这里只算一道 —— 表格那一列叫「已解决」,数条数就名不副实了。
|
||||
* 指定了题号时它最多是 1,不指定时才看得出差别(老师查「这节课全班」就是这种)。
|
||||
*/
|
||||
const solvedFilter = sql`count(distinct ${schema.submission.problemId}) filter (where ${inArray(schema.submission.result, ACCEPTED_RESULTS)})`
|
||||
|
||||
const [[totals], perUser] = await Promise.all([
|
||||
db
|
||||
.select({
|
||||
total: count(),
|
||||
accepted: acceptedFilter.mapWith(Number),
|
||||
judging: judgingFilter.mapWith(Number),
|
||||
})
|
||||
.from(schema.submission)
|
||||
.where(where),
|
||||
db
|
||||
.select({
|
||||
userId: schema.submission.userId,
|
||||
/**
|
||||
* 显示的是**当前**用户名,从 user 表 join 出来 —— 按 submission.username
|
||||
* 分组的话,改过名的学生会裂成新旧两行,两边各算各的,谁都够不到「全做完」。
|
||||
*
|
||||
* 已删号的学生 user 表里没有行,退回提交里冻结的那份名字(下面的
|
||||
* personCount 兜底就是给这种情况的)。
|
||||
*/
|
||||
username: sql<string>`coalesce(${schema.user.username}, max(${schema.submission.username}))`,
|
||||
className: schema.user.className,
|
||||
// 不传用户名时「交了没全对」那一栏靠它把教师和禁用账号挡在外面 ——
|
||||
// 传了用户名时这件事是花名册(rosterRows)做的
|
||||
isDisabled: schema.user.isDisabled,
|
||||
adminType: schema.user.adminType,
|
||||
submissionCount: count(),
|
||||
acceptedCount: acceptedFilter.mapWith(Number),
|
||||
solvedCount: solvedFilter.mapWith(Number),
|
||||
judgingCount: judgingFilter.mapWith(Number),
|
||||
})
|
||||
.from(schema.submission)
|
||||
.leftJoin(schema.user, eq(schema.user.id, schema.submission.userId))
|
||||
.where(where)
|
||||
// user_id 定了 user 那一行就定了,把 username / class_name 一起放进 group by
|
||||
// 不会多分出组来,但省掉再对它们套一层聚合函数
|
||||
.groupBy(
|
||||
schema.submission.userId,
|
||||
schema.user.username,
|
||||
schema.user.className,
|
||||
schema.user.isDisabled,
|
||||
schema.user.adminType,
|
||||
)
|
||||
.orderBy(desc(count())),
|
||||
])
|
||||
|
||||
const submissionCount = totals?.total ?? 0
|
||||
const acceptedCount = totals?.accepted ?? 0
|
||||
const judgingCount = totals?.judging ?? 0
|
||||
// 正确率的分母是**判完的条数**,不是总条数
|
||||
const judgedCount = submissionCount - judgingCount
|
||||
|
||||
/**
|
||||
* 「做完了」的判定。**指定了几道题,就要几道都解决**(这是教师选的口径:
|
||||
* 「今天布置三道,谁全做完了」)—— 做出两道差一道的人落在「交了没全对」那一栏,
|
||||
* 那里带着 `solvedCount`,老师看得出他差几道。
|
||||
*
|
||||
* 只填一道题时 `solvedCount >= 1` 和原来的 `acceptedCount > 0` 完全等价;
|
||||
* 不填题号时无所谓「全部」,退回「至少做出一道」。
|
||||
*/
|
||||
const requiredSolved = scope.problemCount
|
||||
const isDone = (row: { solvedCount: number; acceptedCount: number }) =>
|
||||
requiredSolved > 0
|
||||
? row.solvedCount >= requiredSolved
|
||||
: row.acceptedCount > 0
|
||||
|
||||
/**
|
||||
* 「提交记录」那张表列的是**窗口里交过东西的所有人**,`done` 标出谁做完了 ——
|
||||
* 原来只给做完的人,于是一次没对的学生连同他的提交在这张表里根本不存在,
|
||||
* 教师想看「他到底错在哪」得切到提交列表再翻。展开一行拉的是那个人的全部
|
||||
* 提交(GET /submissions/statistics/items 不按结果过滤),对错都在里面。
|
||||
*
|
||||
* 「完成人数」这些数字跟着 `done` 算,不是 `data.length`。
|
||||
*/
|
||||
const doneCount = perUser.filter(isDone).length
|
||||
// 要等 perUser 回来才能查,所以进不了上面那个 Promise.all
|
||||
const astOnlyByUserMap = await astOnlyByUser(
|
||||
where,
|
||||
perUser.map((row) => row.userId),
|
||||
)
|
||||
|
||||
const submittedUserIds = new Set(perUser.map((row) => row.userId))
|
||||
|
||||
const data = perUser.map((row) => ({
|
||||
username: row.username,
|
||||
className: row.className,
|
||||
submissionCount: row.submissionCount,
|
||||
acceptedCount: row.acceptedCount,
|
||||
solvedCount: row.solvedCount,
|
||||
astOnlyCount: astOnlyByUserMap.get(row.userId) ?? 0,
|
||||
judgingCount: row.judgingCount,
|
||||
correctRate: judgedRate(
|
||||
row.acceptedCount,
|
||||
row.submissionCount - row.judgingCount,
|
||||
),
|
||||
done: isDone(row),
|
||||
}))
|
||||
|
||||
const dataUnaccepted = rosterRows
|
||||
.filter((row) => !submittedUserIds.has(row.id))
|
||||
.map((row) => ({
|
||||
username: row.username,
|
||||
realName: stripClassPrefix(row.username, row.className),
|
||||
}))
|
||||
|
||||
/**
|
||||
* 交了但没做完的:包括一道都没对的,也包括三道里做出两道的。
|
||||
*
|
||||
* **传了用户名时按花名册取**,和 dataUnaccepted 同一个范围,查一个班不会冒出
|
||||
* 一堆别的班的人。
|
||||
*
|
||||
* 不传用户名时没有花名册,这一栏原先跟着空掉 —— 于是只交了错误答案的学生
|
||||
* 「已完成」那张表进不去(没做完)、「未完成」那一栏也没有,整个人从屏幕上
|
||||
* 消失,看起来就像统计只认成功的提交。这种情况退回「有提交但没做完的全部人」,
|
||||
* 教师和禁用账号照样排除(否则老师自己试题留下的错误提交会混进点名名单)。
|
||||
*
|
||||
* 「还没交」那一栏没有花名册是真的算不出来(不知道该有谁),仍然为空。
|
||||
*/
|
||||
const rosterIds = new Set(rosterRows.map((row) => row.id))
|
||||
const attemptedRows = perUser.filter((row) => {
|
||||
if (isDone(row)) return false
|
||||
return username
|
||||
? rosterIds.has(row.userId)
|
||||
: !row.isDisabled && row.adminType === "Regular User"
|
||||
})
|
||||
const failureByUser = await lastFailureByUser(
|
||||
where,
|
||||
attemptedRows.map((row) => row.userId),
|
||||
)
|
||||
const dataAttempted = attemptedRows.map((row) => ({
|
||||
username: row.username,
|
||||
/**
|
||||
* 剥前缀只在**查了某个班**的时候做:那时满屏都是同一个班,留着 `ks251` 是噪音。
|
||||
* 不传用户名的全站视图里各班混在一起,剥完只剩一串重名的名字,反而认不出谁,
|
||||
* 所以原样给完整用户名。班名取 perUser join 出来的那一列,和花名册同一份数据。
|
||||
*/
|
||||
realName: username
|
||||
? stripClassPrefix(row.username, row.className)
|
||||
: row.username,
|
||||
submissionCount: row.submissionCount,
|
||||
solvedCount: row.solvedCount,
|
||||
lastFailure: failureByUser.get(row.userId) ?? null,
|
||||
}))
|
||||
|
||||
// 「学生已删号但提交记录还在」时完成人数会大于花名册人数,分母兜到完成人数为止。
|
||||
// 旧后端在这之前还先算了一个 person_rate 一起下发,前端从来没读过它(完成度是
|
||||
// 前端自己按「减掉请假人数之后的分母」重算的),所以这条链路上只留 person_count。
|
||||
let personCount = rosterRows.length
|
||||
if (personCount && personCount < doneCount) personCount = doneCount
|
||||
|
||||
return success(c, {
|
||||
submissionCount,
|
||||
acceptedCount,
|
||||
judgingCount,
|
||||
correctRate: judgedRate(acceptedCount, judgedCount),
|
||||
personCount,
|
||||
data,
|
||||
dataUnaccepted,
|
||||
dataAttempted,
|
||||
} satisfies SubmissionStatistics)
|
||||
})
|
||||
|
||||
/**
|
||||
* 统计面板展开一行时拉这个人的提交明细。
|
||||
*
|
||||
* 用户名这里是**精确匹配**,不是统计接口那种 ilike —— 那边填 `ks251` 要圈出整个班,
|
||||
* 这边是「点开的这一行是谁」。时间窗和题号沿用同一个 scope,不然展开行看到的
|
||||
* 会是另一个范围的数据。
|
||||
*/
|
||||
submissionRoutes.get(
|
||||
"/submissions/statistics/items",
|
||||
requireTeacher,
|
||||
async (c) => {
|
||||
const username = c.req.query("username")?.trim()
|
||||
if (!username)
|
||||
return failure(c, 400, "invalid-request", "username is required")
|
||||
|
||||
const scope = await statisticsScope(c)
|
||||
if (!scope.ok) return failure(c, scope.status, scope.code, scope.message)
|
||||
|
||||
/**
|
||||
* 展开的那一行给的是**当前**用户名,先换成 user_id 再查 —— 直接按
|
||||
* `submission.username` 精确匹配的话,改过名的学生展开来是空的(他的提交
|
||||
* 全挂在旧名字下)。
|
||||
*
|
||||
* 查不到账号才退回按提交里冻结的用户名匹配:已删号的学生仍然会出现在统计
|
||||
* 表格里(那一行的名字取自提交),展开行不能因此空着。
|
||||
*/
|
||||
const [account] = await db
|
||||
.select({ id: schema.user.id })
|
||||
.from(schema.user)
|
||||
.where(eq(schema.user.username, username))
|
||||
.limit(1)
|
||||
const identity = account
|
||||
? eq(schema.submission.userId, account.id)
|
||||
: eq(schema.submission.username, username)
|
||||
|
||||
// 多取一条,好知道是不是被截断了
|
||||
// innerJoin 不会漏行:submission.problem_id 是 NOT NULL 且外键是 NO ACTION,
|
||||
// 题目删不掉(真要删会被外键拦住并提示改为隐藏)
|
||||
const rows = await db
|
||||
.select({
|
||||
id: schema.submission.id,
|
||||
result: schema.submission.result,
|
||||
createTime: schema.submission.createTime,
|
||||
problem: schema.problem.displayId,
|
||||
problemTitle: schema.problem.title,
|
||||
})
|
||||
.from(schema.submission)
|
||||
.innerJoin(
|
||||
schema.problem,
|
||||
eq(schema.problem.id, schema.submission.problemId),
|
||||
)
|
||||
.where(and(...scope.filters, identity))
|
||||
.orderBy(desc(schema.submission.createTime), desc(schema.submission.id))
|
||||
.limit(STATISTICS_ITEMS_LIMIT + 1)
|
||||
|
||||
const truncated = rows.length > STATISTICS_ITEMS_LIMIT
|
||||
return success(c, {
|
||||
items: rows.slice(0, STATISTICS_ITEMS_LIMIT),
|
||||
truncated,
|
||||
} satisfies SubmissionStatisticsItems)
|
||||
},
|
||||
)
|
||||
submissionRoutes.route("/", submissionStatisticsRoutes)
|
||||
|
||||
submissionRoutes.post(
|
||||
"/submissions/:id/rejudge",
|
||||
|
||||
@@ -16,7 +16,8 @@
|
||||
*
|
||||
* 加路由时顺手跑一下,比事后靠人眼在 200 多条路由里看出顺序问题可靠。
|
||||
*
|
||||
* 局限:靠正则读源码,只认 `xxxRoutes.get("字面量", …)` 这种写法。
|
||||
* 局限:靠正则读源码,只认 `xxxRoutes.get("字面量", …)` 这种写法,
|
||||
* 以及 `xxxRoutes.route("字面量", 子路由)` 的嵌套挂载(按挂载位置展开)。
|
||||
* 动态拼出来的路径看不见 —— 但本仓库没有那种写法,加的时候请保持。
|
||||
*/
|
||||
|
||||
@@ -74,15 +75,22 @@ function collect(): Route[] {
|
||||
const file = routerFile.get(router)
|
||||
if (!file) return []
|
||||
const text = readFileSync(file, "utf8")
|
||||
// 直接注册的路由和嵌套挂载(`router.route("/", child)`)放在一起按出现位置排序:
|
||||
// 子路由挂在哪个位置,它的路由就在哪个位置参与匹配
|
||||
const pattern = new RegExp(
|
||||
`${router}\\.(get|post|put|delete|patch)\\(\\s*"([^"]+)"`,
|
||||
`${router}\\.(get|post|put|delete|patch)\\(\\s*"([^"]+)"|${router}\\.route\\(\\s*"([^"]*)"\\s*,\\s*(\\w+)\\s*\\)`,
|
||||
"g",
|
||||
)
|
||||
return [...text.matchAll(pattern)].map((m) => ({
|
||||
method: m[1]!.toUpperCase(),
|
||||
path: (prefix + m[2]!).replace(/\/+/g, "/").replace(/\/$/, "") || "/",
|
||||
file: file.replace(SRC + "/", ""),
|
||||
}))
|
||||
return [...text.matchAll(pattern)].flatMap((m) => {
|
||||
if (m[4]) return routesOf(m[4], prefix + m[3]!)
|
||||
return [
|
||||
{
|
||||
method: m[1]!.toUpperCase(),
|
||||
path: (prefix + m[2]!).replace(/\/+/g, "/").replace(/\/$/, "") || "/",
|
||||
file: file.replace(SRC + "/", ""),
|
||||
},
|
||||
]
|
||||
})
|
||||
}
|
||||
|
||||
// 挂载顺序就是匹配顺序,所以必须按 index.ts 里出现的先后来摊平
|
||||
|
||||
Reference in New Issue
Block a user