- 随便来一道:按学生在编辑器里上次用的语言挑(没用过按 Python),C 学生不再抽到 Python 专用题和 SQL 题,Python 学生不再抽到 SQL 题;选了 SQL 知识点或 SQL 类型才从 SQL 题里抽。也跟着「全部类型」的筛选走 - 老师那一版去掉「只看没做完」:没有状态列,开了只是题少了 - 题目页「相似题目」:流程图评到 A / S 的题也算做对,不再推荐,和列表打勾一个口径 Co-Authored-By: Claude Opus 5.5 <noreply@anthropic.com>
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@@ -1,4 +1,5 @@
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import {
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normalizeLanguage,
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problemListSortSchema,
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problemTypeFilterSchema,
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type ProblemAuthor,
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@@ -6,6 +7,7 @@ import {
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type ProblemList,
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type ProblemListItem,
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type ProblemProgress,
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type ProblemTypeFilter,
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type Tag,
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} from "@oj2/contract"
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import {
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@@ -81,6 +83,15 @@ async function getProblemTags(problemIds: number[]) {
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return result
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}
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/** 「全部类型」下拉的筛选条件,列表和「随便来一道」共用 */
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function typeFilter(type: ProblemTypeFilter | undefined) {
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if (type === "reference") return eq(schema.problem.showFlowchart, true)
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if (type === "flowchart") return eq(schema.problem.allowFlowchart, true)
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if (type === "ast") return sql`${schema.problem.astRules} is not null`
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if (type === "sql") return sql`${schema.problem.languages} @> '["SQL"]'::jsonb`
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return undefined
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}
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type ProblemStates = Awaited<ReturnType<typeof problemStates>> | null
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type UserCounts = Awaited<ReturnType<typeof problemUserCounts>>
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@@ -155,10 +166,8 @@ problemRoutes.get("/problems", optionalAuth, async (c) => {
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),
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)
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}
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if (type === "reference") filters.push(eq(schema.problem.showFlowchart, true))
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if (type === "flowchart") filters.push(eq(schema.problem.allowFlowchart, true))
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if (type === "ast") filters.push(sql`${schema.problem.astRules} is not null`)
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if (type === "sql") filters.push(sql`${schema.problem.languages} @> '["SQL"]'::jsonb`)
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const byType = typeFilter(type)
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if (byType) filters.push(byType)
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const states = user ? await problemStates(user.id) : null
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if (undone && states && states.solved.size > 0)
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@@ -254,12 +263,22 @@ problemRoutes.get("/problem-tags", async (c) => {
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})
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/**
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* 「随便来一道」:范围是当前知识点(不传就是全部),先挑自己还没做对的简单 / 中等题,
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* 没有就放宽到没做对的困难题,再没有就随便一道(全做对了也给一道,不让按钮落空)。
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* 「随便来一道」:范围是当前知识点和类型(不传就是全部),先挑能用自己的语言做的、
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* 还没做对的简单 / 中等题,没有就一档档放宽:没做对的困难题 → 做对过的
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* (全做对了也给一道,不让按钮落空)→ 别的语言的题。
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*
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* 语言是前端记着的「上次用的语言」,没有就是 Python。不按语言挑的话,C 学生大约每
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* 9 次就抽到 1 道没有 C 的题(Python 专用题和 SQL 题)。语言排在最前、而不是筛掉:
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* 选了「SQL」知识点时没有一道能用 Python 做,照样得抽一道 SQL 题出来。
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*/
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problemRoutes.get("/problems/random", optionalAuth, async (c) => {
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const user = c.get("user")
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const tag = c.req.query("tag")?.trim()
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const type = problemTypeFilterSchema.safeParse(c.req.query("type")).data
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// 上次用的是 SQL(刚做完一道 SQL 题)不算偏好:SQL 题一共 9 道,照它挑就成了「随便来一道
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// SQL」。要 SQL 题的人会选「SQL」知识点或类型,那时按上面说的照样抽得到
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const saved = normalizeLanguage(c.req.query("language"))
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const language = saved && saved !== "SQL" && saved !== "Flowchart" ? saved : "Python"
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const states = user ? await problemStates(user.id) : null
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const solved = states ? [...states.solved] : []
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const [row] = await db
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@@ -282,11 +301,13 @@ problemRoutes.get("/problems/random", optionalAuth, async (c) => {
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.where(eq(schema.problemTag.name, tag)),
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)
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: undefined,
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typeFilter(type),
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),
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)
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// 没做对过题(没登录、新生)就不排这一项。别拿 sql`1` 占位:ORDER BY 里的整数常量是
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// 「按第 1 列排」,会先按题号排、random() 形同虚设,每次都是同一道
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.orderBy(
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desc(sql`${schema.problem.languages} @> ${JSON.stringify([language])}::jsonb`),
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...(solved.length ? [asc(inArray(schema.problem.id, solved))] : []),
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asc(sql`${schema.problem.difficulty} = 'High'`),
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sql`random()`,
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@@ -337,11 +358,13 @@ problemRoutes.get("/problems/:displayId/similar", optionalAuth, async (c) => {
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// 「已 AC 的不再推荐」必须下推到 SQL。早先是先 limit(5) 再在内存里筛,刷题多的
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// 学生 5 条候选能被筛到只剩一两条、甚至清零(前端 v-if 一空整块就不渲染)——
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// 而这个接口恰好只在**刚 AC** 或**连挂三次**时才被调用,正是候选最容易全中的时候。
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const statuses = await getProblemStatuses(c.get("user")?.id)
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const solvedIds = Object.entries(statuses)
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.filter(([, value]) => asRecord(value).status === JudgeStatus.ACCEPTED)
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.map(([key]) => Number(key))
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.filter((id) => Number.isInteger(id))
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// 做对了的和题目列表同一个口径:画流程图的题,流程图评到 A / S 也算(problemStates)
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const user = c.get("user")
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const [statuses, states] = await Promise.all([
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getProblemStatuses(user?.id),
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user ? problemStates(user.id) : null,
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])
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const solvedIds = states ? [...states.solved] : []
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// difficulty 是 text(Low / Mid / High),直接 order by 走的是字典序 ——
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// High 排在 Low 前面,「由易到难」会变成「最难的先上」。按语义显式排。
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const difficultyRank = sql`case ${schema.problem.difficulty} when 'Low' then 0 when 'Mid' then 1 else 2 end`
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@@ -388,7 +411,7 @@ problemRoutes.get("/problems/:displayId/similar", optionalAuth, async (c) => {
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const [tags, counts] = await Promise.all([getProblemTags(ids), problemUserCounts(ids)])
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return success(
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c,
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rows.map((row) => listItem(row, tags, statuses, null, counts)),
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rows.map((row) => listItem(row, tags, statuses, states, counts)),
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)
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})
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@@ -100,9 +100,12 @@ export function getProblemProgress() {
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return api.get<ProblemProgress | null>("problems/progress")
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}
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/** 「随便来一道」:当前知识点里先挑自己没做对的简单 / 中等题,返回题号 */
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export function getRandomProblem(tag: string) {
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return api.get<string>("problems/random", { params: tag ? { tag } : {} })
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/**
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* 「随便来一道」:当前知识点和类型里,先挑能用 language 做的、自己没做对的简单 / 中等题,
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* 返回题号。空串的参数拦截器会去掉
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*/
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export function getRandomProblem(params: { tag: string; type: string; language: string }) {
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return api.get<string>("problems/random", { params })
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}
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export function getAuthors(all = false) {
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@@ -4,6 +4,7 @@ import type { ProblemProgress, ProblemTypeFilter, Tag } from "@oj2/contract"
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import { useRouteQuery } from "@vueuse/router"
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import { useThemeVars } from "naive-ui"
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import { getAuthors, getProblemList, getProblemProgress, getRandomProblem } from "oj/api"
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import { useCodeStore } from "oj/store/code"
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import { useTone } from "oj/submission/composables/tone"
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import { STORAGE_KEY } from "utils/constants"
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import storage from "utils/storage"
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@@ -54,6 +55,7 @@ const userStore = useUserStore()
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const authStore = useAuthModalStore()
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const theme = useThemeVars()
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const tone = useTone()
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const codeStore = useCodeStore()
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const { isDesktop, isMobile } = useBreakpoints()
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const { query } = usePagination<ProblemQuery>(
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@@ -69,11 +71,6 @@ const { query } = usePagination<ProblemQuery>(
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{ defaultLimit: 30 },
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)
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const undoneOn = computed({
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get: () => query.undone === "1",
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set: (on: boolean) => (query.undone = on ? "1" : ""),
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})
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const problems = ref<ProblemRow[]>([])
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const total = ref(0)
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const loaded = ref(false)
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@@ -86,6 +83,12 @@ const teacher = computed(() => userStore.isTeacherOrAbove)
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const showStatus = computed(() => userStore.isAuthed && !teacher.value)
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const mine = computed(() => (showStatus.value ? progress.value : null))
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// 老师那一版没有这个开关:没有状态列,开了也看不出藏了哪些题。带着 ?undone=1 进来也当没开
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const undoneOn = computed({
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get: () => query.undone === "1" && !teacher.value,
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set: (on: boolean) => (query.undone = on ? "1" : ""),
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})
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const tagByName = computed(() => new Map(tags.value.map((t) => [t.name, t])))
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const currentTag = computed(() => tagByName.value.get(query.tag) ?? null)
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const startTag = computed(() => tagByName.value.get(START_TAG) ?? null)
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@@ -279,7 +282,12 @@ const picking = ref(false)
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async function pickRandom() {
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picking.value = true
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try {
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const id = await getRandomProblem(query.tag)
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const id = await getRandomProblem({
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tag: query.tag,
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type: query.type,
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// 只挑能用自己的语言做的题:学生在编辑器里上次用的语言,没用过就是 Python
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language: codeStore.preferredLanguage(),
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})
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router.push("/problem/" + id)
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} finally {
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picking.value = false
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@@ -511,8 +519,9 @@ const gridColumns = computed(() =>
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:consistent-menu-width="false"
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:options="sortOptions"
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/>
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<span class="vsep"></span>
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<span v-if="!teacher" class="vsep"></span>
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<label
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v-if="!teacher"
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class="undone"
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:class="{ disabled: !userStore.isAuthed }"
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:title="userStore.isAuthed ? '做对的题藏起来' : '登录后才能用'"
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@@ -665,7 +674,7 @@ const gridColumns = computed(() =>
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@update:value="(v: string | null) => (query.author = v ?? '')"
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/>
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<n-select v-model:value="query.sort" size="small" :options="sortOptions" />
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<label class="undone" :class="{ disabled: !userStore.isAuthed }">
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<label v-if="!teacher" class="undone" :class="{ disabled: !userStore.isAuthed }">
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<n-switch v-model:value="undoneOn" size="small" :disabled="!userStore.isAuthed" />
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只看没做完
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</label>
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