feat(流程图): 流程图画到 A / S 算这道题做完——题单进度、课堂条都认;加入题单之前画的图先藏起来
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- 流程图评到 A 或 S,记进所有已加入、且包含这道题的题单(和判题那一路同一个口径,不看从哪个
  入口交的),徽章和题单类成就照样推送。原来题单进度只在判代码时记,流程图作业在题单里永远是
  「没做」。流程图提交的 id 进不了 problemset_submission(外键指向代码提交表),所以只写
  progress_detail —— 解锁旧提交的那道闸看的也是它
- 课堂条(/me/class-activity)的 myStatus:流程图 A / S 也算 accepted,评完的非 A/S 算 tried
- 题单防抄闸门补到流程图上:加入题单之前画的图,对本人藏起来(列表 showLink、详情 404、
  current / history 不数它),规则和代码提交同一份(problemSetJoinTimes 挪进 services/problemset)。
  原来加入之前画到 A 的那张图点一下就能载回画布、交上去就是 A
- 新增 GET /problems/:id/flowchart/scores:一次给出自己评完的每一次的分数和等级,外加被藏起来
  的次数(原来 history 一次只给一条,看分数走势得一页一页翻)
- 「A/S 算过关」和按分数定等级收进 flowchart/grade.ts;判题那边的记账 + 通知抽成
  recordSolvedAndNotify,两条路共用

Co-Authored-By: Claude Opus 5.5 <noreply@anthropic.com>
This commit is contained in:
xuyueandClaude Opus 5.5 committed 2026-09-28 17:56:35 +08:00
1 parent 948e9a734d
commit 3fe3caa944
8 files changed
+280 -145

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+24
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@@ -17,6 +17,7 @@ import { Hono } from "hono"
import { requireAuth, requireTeacher, type AppEnv } from "../auth/middleware"
import { db, schema } from "../db"
import { failure, parseBody, success } from "../http"
import { FLOWCHART_PASS_GRADES } from "../flowchart/grade"
import { JudgeStatus } from "../judge/status"
import { calendarDay, dayStart, localTime } from "../time"
import { queryInteger, rounded } from "./helpers"
@@ -326,6 +327,29 @@ classroomRoutes.get("/me/class-activity", requireAuth, async (c) => {
: []
const mineById = new Map(mine.map((row) => [row.problemId, row.accepted]))
// 流程图作业:画到 A / S 也算做完(设计文档 2026-09-28-problem-page-redesign 第 3 节决定 6)。
// 有的题流程图交了几百次、代码个位数,只看代码提交的话,这些学生在课堂条上永远是「没做」
const drawn = ids.length
? await db
.select({
problemId: schema.flowchartSubmission.problemId,
passed: sql<boolean>`bool_or(${inArray(schema.flowchartSubmission.aiGrade, FLOWCHART_PASS_GRADES)})`,
})
.from(schema.flowchartSubmission)
.where(
and(
eq(schema.flowchartSubmission.userId, user.id),
inArray(schema.flowchartSubmission.problemId, ids),
// 只数评完了的:评分中、评失败的那次不算「做过」
eq(schema.flowchartSubmission.status, 2),
),
)
.groupBy(schema.flowchartSubmission.problemId)
: []
for (const row of drawn) {
mineById.set(row.problemId, (mineById.get(row.problemId) ?? false) || row.passed)
}
return success(c, {
className: user.className,
day: lesson.day,
+92 -40
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@@ -5,6 +5,7 @@ import {
type CreateFlowchartResponse,
type FlowchartCurrent,
type FlowchartDetail,
type FlowchartScores,
type FlowchartList,
type FlowchartListItem,
type FlowchartStatistics,
@@ -14,11 +15,13 @@ import { and, asc, count, desc, eq, inArray, isNull, sql, type SQL } from "drizz
import { Hono } from "hono"
import { requireAuth, requireTeacher, type AppEnv } from "../auth/middleware"
import type { AuthUser } from "../auth/session"
import { config } from "../config"
import { db, schema } from "../db"
import { failure, readJson, success } from "../http"
import { flowchartQueue } from "../queue"
import { getBooleanOption } from "../services/options"
import { problemSetJoinTimes } from "../services/problemset"
import { consumeToken } from "../services/throttling"
import { buildWordFrequencies } from "../services/word-frequency"
import { dayStart } from "../time"
@@ -38,14 +41,38 @@ function flowchartThrottleKey(userId: number) {
return `flowchart:${userId}`
}
function canView(
user: import("../auth/session").AuthUser,
row: { userId: number },
problem: { createdById: number },
/**
* 题单防抄:学生加入含这道题的题单之前画的图,先对他本人藏起来 —— 和代码提交同一道闸
* (routes/submission.ts 的 canViewSubmission,规则见 problemSetJoinTimes)。原来流程图
* 这边没有这一条,加入题单之前画到 A 的那张图点一下就能载回画布,交上去就是 A。
*/
function hiddenByProblemSet(
user: AuthUser,
row: { userId: number; problemId: number; createTime: string },
joinTimes: Map<number, string>,
) {
if (row.userId !== user.id || isAdminRole(user)) return false
const joinTime = joinTimes.get(row.problemId)
return joinTime !== undefined && Date.parse(row.createTime) < Date.parse(joinTime)
}
function canView(
user: AuthUser,
row: { userId: number; problemId: number; createTime: string },
problem: { createdById: number },
joinTimes: Map<number, string>,
) {
if (hiddenByProblemSet(user, row, joinTimes)) return false
return row.userId === user.id || isAdminRole(user) || problem.createdById === user.id
}
/** 只有学生看自己的提交时才需要查题单;其余情况给一张空表,省一次查询 */
function joinTimesFor(user: AuthUser, rows: Array<{ userId: number; problemId: number }>) {
if (isAdminRole(user)) return Promise.resolve(new Map<number, string>())
const own = rows.filter((row) => row.userId === user.id).map((row) => row.problemId)
return problemSetJoinTimes(user.id, [...new Set(own)])
}
function flowchartData(
flowchart: typeof schema.flowchartSubmission.$inferSelect,
username: string,
@@ -188,8 +215,9 @@ async function flowchartUserFilter(username: string) {
const flowchartListColumns = {
flowchart: {
id: schema.flowchartSubmission.id,
// showLink 判定要,序列化本身用不到
// showLink 判定要(本人 + 题单闸门),序列化本身用不到
userId: schema.flowchartSubmission.userId,
problemId: schema.flowchartSubmission.problemId,
status: schema.flowchartSubmission.status,
createTime: schema.flowchartSubmission.createTime,
aiScore: schema.flowchartSubmission.aiScore,
@@ -250,6 +278,10 @@ flowchartRoutes.get("/flowcharts", requireAuth, async (c) => {
.limit(limit)
.offset(offset),
])
const joinTimes = await joinTimesFor(
user,
rows.map((row) => row.flowchart),
)
return success(c, {
results: rows.map(
({ flowchart, username, problem }) =>
@@ -266,7 +298,7 @@ flowchartRoutes.get("/flowcharts", requireAuth, async (c) => {
aiModel: flowchart.aiModel,
processingTime: flowchart.processingTime,
evaluationTime: flowchart.evaluationTime,
showLink: canView(user, flowchart, problem),
showLink: canView(user, flowchart, problem, joinTimes),
}) satisfies FlowchartListItem,
),
total: totalRows[0]?.value ?? 0,
@@ -514,7 +546,8 @@ flowchartRoutes.get("/flowcharts/:id", requireAuth, async (c) => {
.innerJoin(schema.problem, eq(schema.flowchartSubmission.problemId, schema.problem.id))
.where(eq(schema.flowchartSubmission.id, c.req.param("id")))
.limit(1)
if (!row || !canView(c.get("user")!, row.flowchart, row.problem))
const user = c.get("user")!
if (!row || !canView(user, row.flowchart, row.problem, await joinTimesFor(user, [row.flowchart])))
return failure(c, 404, "flowchart-not-found", "Submission does not exist")
return success(c, flowchartData(row.flowchart, row.username))
})
@@ -527,7 +560,7 @@ flowchartRoutes.post("/flowcharts/:id/retry", requireAuth, async (c) => {
.innerJoin(schema.problem, eq(schema.flowchartSubmission.problemId, schema.problem.id))
.where(eq(schema.flowchartSubmission.id, c.req.param("id")))
.limit(1)
if (!row || !canView(user, row.flowchart, row.problem))
if (!row || !canView(user, row.flowchart, row.problem, await joinTimesFor(user, [row.flowchart])))
return failure(c, 404, "flowchart-not-found", "Submission does not exist")
if (![2, 3].includes(row.flowchart.status))
return failure(c, 409, "retry-not-allowed", "Submission is not in a state that allows retry")
@@ -582,47 +615,48 @@ flowchartRoutes.post("/flowcharts/:id/retry", requireAuth, async (c) => {
} satisfies CreateFlowchartResponse)
})
/**
* 自己在这道题上评完的每一次,按时间从早到晚,已经滤掉加入题单之前的(题单闸门)。
* current / history / scores 三个接口都从这一份出。
*/
async function myEvaluatedFlowcharts(user: AuthUser, problemId: number) {
const [rows, joinTimes] = await Promise.all([
db
.select({
flowchart: schema.flowchartSubmission,
username: schema.user.username,
})
.from(schema.flowchartSubmission)
.innerJoin(schema.user, eq(schema.flowchartSubmission.userId, schema.user.id))
.where(
and(
eq(schema.flowchartSubmission.userId, user.id),
eq(schema.flowchartSubmission.problemId, problemId),
eq(schema.flowchartSubmission.status, 2),
),
)
.orderBy(asc(schema.flowchartSubmission.createTime)),
joinTimesFor(user, [{ userId: user.id, problemId }]),
])
const visible = rows.filter((row) => !hiddenByProblemSet(user, row.flowchart, joinTimes))
return { visible, hidden: rows.length - visible.length }
}
flowchartRoutes.get("/problems/:id/flowchart/current", requireAuth, async (c) => {
const problemId = queryInteger(c.req.param("id"), 0, { min: 1 })
const rows = await db
.select({
score: schema.flowchartSubmission.aiScore,
grade: schema.flowchartSubmission.aiGrade,
})
.from(schema.flowchartSubmission)
.where(
and(
eq(schema.flowchartSubmission.userId, c.get("user")!.id),
eq(schema.flowchartSubmission.problemId, problemId),
eq(schema.flowchartSubmission.status, 2),
),
)
.orderBy(desc(schema.flowchartSubmission.createTime))
const { visible } = await myEvaluatedFlowcharts(c.get("user")!, problemId)
const latest = visible.at(-1)?.flowchart
return success(c, {
count: rows.length,
score: rows[0]?.score ?? 0,
grade: rows[0]?.grade ?? "",
count: visible.length,
score: latest?.aiScore ?? 0,
grade: latest?.aiGrade ?? "",
} satisfies FlowchartCurrent)
})
flowchartRoutes.get("/problems/:id/flowchart/history", requireAuth, async (c) => {
const problemId = queryInteger(c.req.param("id"), 0, { min: 1 })
const page = queryInteger(c.req.query("page"), 0, { min: 0 })
const rows = await db
.select({
flowchart: schema.flowchartSubmission,
username: schema.user.username,
})
.from(schema.flowchartSubmission)
.innerJoin(schema.user, eq(schema.flowchartSubmission.userId, schema.user.id))
.where(
and(
eq(schema.flowchartSubmission.userId, c.get("user")!.id),
eq(schema.flowchartSubmission.problemId, problemId),
eq(schema.flowchartSubmission.status, 2),
),
)
.orderBy(asc(schema.flowchartSubmission.createTime))
const { visible: rows } = await myEvaluatedFlowcharts(c.get("user")!, problemId)
const selected = page === 0 ? rows.at(-1) : rows[page - 1]
if (page > rows.length) return failure(c, 400, "page-out-of-range", "Page out of range")
return success(c, {
@@ -630,3 +664,21 @@ flowchartRoutes.get("/problems/:id/flowchart/history", requireAuth, async (c) =>
count: rows.length,
} satisfies FlowchartDetail)
})
/**
* 历次分数:结果页签上那一排「第 N 次 xx 分」。原来 history 一次只给一条,
* 要看分数走势得一页一页翻。`hidden` 是被题单闸门藏起来的次数,界面上给一句说明。
*/
flowchartRoutes.get("/problems/:id/flowchart/scores", requireAuth, async (c) => {
const problemId = queryInteger(c.req.param("id"), 0, { min: 1 })
const { visible, hidden } = await myEvaluatedFlowcharts(c.get("user")!, problemId)
return success(c, {
scores: visible.map(({ flowchart }) => ({
id: flowchart.id,
score: flowchart.aiScore ?? 0,
grade: flowchart.aiGrade ?? "",
createTime: flowchart.createTime,
})),
hidden,
} satisfies FlowchartScores)
})
+2 -48
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@@ -10,7 +10,7 @@ import {
type SubmissionListItem,
type SubmissionTrace,
} from "@oj2/contract"
import { and, count, desc, eq, gt, inArray, isNull, or, sql, type SQL } from "drizzle-orm"
import { and, count, desc, eq, inArray, isNull, sql, type SQL } from "drizzle-orm"
import { Hono } from "hono"
import { optionalAuth, requireAuth, requireSuperAdmin } from "../auth/middleware"
@@ -28,6 +28,7 @@ import {
} from "../services/contest"
import { CodeFormatError, formatCode } from "../services/format-code"
import { getBooleanOption } from "../services/options"
import { problemSetJoinTimes } from "../services/problemset"
import { consumeToken } from "../services/throttling"
import { dayStart } from "../time"
import { asFilterValue, asRecord, isAdminRole, queryInteger } from "./helpers"
@@ -248,53 +249,6 @@ submissionRoutes.post("/code/format", requireAuth, async (c) => {
}
})
/**
* 题单防作弊闸门:查出这些题目里,哪些题的旧提交要对该用户藏起来,返回 problemId → 加入时间。
*
* 对齐旧后端 `submission/serializers.py:12` 的 `bulk_fetch_problemset_progress`。学生加入含
* 某道题的题单后,他在加入之前留下的 AC 代码还摆在提交列表里,复制粘贴就能把题单刷完。
* 备份快照里 1734 人次、188 名学生进过这个窗口(占已解题次的 22.5%),不是边角情况。
*
* 解锁的三条路全写在 where 里,任一成立就查不出来、也就不遮挡:
* - 已经在题单里做出这道题(progress_detail 里有这道题的 key)
* - 题单过了截止时间(end_time;为空表示不设期限,只能靠做出来解锁)
* - 题单被归档(status 不是 active)
*
* 一道题可能同时落在多个已加入的题单里,取最晚的 join_time——「存在任一题单要求遮挡就遮挡」
* 等价于「提交时间早于最晚的那次加入」。旧后端这里用 `.first()` 取任意一条,一题多题单时
* 行为不确定,换成聚合顺手定死。
*/
async function problemSetJoinTimes(userId: number, problemIds: number[]) {
const joinTimes = new Map<number, string>()
if (problemIds.length === 0) return joinTimes
const rows = await db
.select({
problemId: schema.problemsetProblem.problemId,
// 聚合表达式不走列的类型映射,但 OID 还是 1184 —— db/index.ts 给这个 OID 挂了
// 「转成 ISO 8601」的 parser,所以这里拿到的和 `mode:"string"` 的列同形状。
// 原来那个 `::text` 要撤掉:它的 OID 是 25、绕过那个 parser,反而会变成 PG 文本。
joinTime: sql<string>`max(${schema.problemsetProgress.joinTime})`,
})
.from(schema.problemsetProgress)
.innerJoin(schema.problemset, eq(schema.problemset.id, schema.problemsetProgress.problemsetId))
.innerJoin(
schema.problemsetProblem,
eq(schema.problemsetProblem.problemsetId, schema.problemset.id),
)
.where(
and(
eq(schema.problemsetProgress.userId, userId),
inArray(schema.problemsetProblem.problemId, problemIds),
eq(schema.problemset.status, "active"),
or(isNull(schema.problemset.endTime), gt(schema.problemset.endTime, sql`now()`)),
sql`not jsonb_exists(${schema.problemsetProgress.progressDetail}, ${schema.problemsetProblem.problemId}::text)`,
),
)
.groupBy(schema.problemsetProblem.problemId)
for (const row of rows) joinTimes.set(row.problemId, row.joinTime)
return joinTimes
}
// 参数按「实际用到的字段」声明,而不是整行 $inferSelect:列表接口只 select 需要的列,
// 传不进完整行。完整行在结构上满足这两个窄类型,详情接口照旧调用不受影响。
function canViewSubmission(